A1025

Myth丶恋晨 2024-04-17 05:22 81阅读 0赞

Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now it is your job to write a program to correctly merge all the ranklists and generate the final rank.

### Input Specification: ###

Each input file contains one test case. For each case, the first line contains a positive number *N* (≤100), the number of test locations. Then *N* ranklists follow, each starts with a line containing a positive integer *K* (≤300), the number of testees, and then *K* lines containing the registration number (a 13-digit number) and the total score of each testee. All the numbers in a line are separated by a space.

### Output Specification: ###

For each test case, first print in one line the total number of testees. Then print the final ranklist in the following format:

registration_number final_rank location_number local_rank

The locations are numbered from 1 to *N*. The output must be sorted in nondecreasing order of the final ranks. The testees with the same score must have the same rank, and the output must be sorted in nondecreasing order of their registration numbers.

### Sample Input: ###

2
    5
    1234567890001 95
    1234567890005 100
    1234567890003 95
    1234567890002 77
    1234567890004 85
    4
    1234567890013 65
    1234567890011 25
    1234567890014 100
    1234567890012 85

### Sample Output: ###

9
    1234567890005 1 1 1
    1234567890014 1 2 1
    1234567890001 3 1 2
    1234567890003 3 1 2
    1234567890004 5 1 4
    1234567890012 5 2 2
    1234567890002 7 1 5
    1234567890013 8 2 3
    1234567890011 9 2 4

### code: ###

#include<cstdio> 
    #include<cstring>
    #include<algorithm>
    #include<iostream>
    using namespace std;
    
    struct Student{ 
    	char id[15]; //准考证号 
    	int score; //分数 
    	int location_number; //考场号 
    	int local_rank; // 考场内排名 
    }stu[30010];
    
    bool cmp(Student a, Student b){ 
    	if (a.score!=b.score) return a.score>b.score; //分数从高到底排序 
    	else return strcmp(a.id,b.id)<0; //分数相同,按照准考证从小到大 
    }
    
    int main(){ 
    	int n, k, num=0; //num总考生数 
    	cin>>n; //n考场数 
    	
    	for(int i=1; i<=n; i++){ 
    		scanf("%d",&k); //该考场人数 
    		for(int j=0;j<k;j++){ 
    			scanf("%s %d",stu[num].id, &stu[num].score); // 准考证号 , 成绩 
    			stu[num].location_number=i; // 考场号为i 
    			num++; //总考生数 ++ 
    		}	
    		
    		//cout<<num<<" "<<k; num 9 k 4
    		sort(stu+num-k, stu+num, cmp);
    		//cout<<stu[num-k].id; 1234567890014
    		stu[num-k].local_rank=1; //该考场第一名 rank 1 
    	
    		for(int j=num-k+1; j<num; j++){ 
    			if(stu[j].score==stu[j-1].score){  //与前一名分数相同 
    				stu[j].local_rank = stu[j-1].local_rank;
    			}
    			else{ 
    				stu[j].local_rank = j+1-(num-k);
    			}
    		}
    	}
    
    	
    	cout<<num<<endl;//输出总考生数 
    	
    	sort(stu, stu+num, cmp) ;//对所有考生排序; 
    // cout<<stu[1].local_rank; 
    	
    	int r=1;
    	for(int i=0; i<num; i++){ 
    		if(i>0 && stu[i].score!=stu[i-1].score){ 
    			r=i+1;
    		}
    		cout<<stu[i].id<<" ";
    		cout<<r<<" "<<stu[i].location_number<<" "<<stu[i].local_rank<<endl;
    	}
    	
    	return 0;
    }