1082 Read Number in Chinese (25 分) PAT 甲级字符串处理 1082 我的代码+别人的代码

小灰灰 2024-02-19 21:27 65阅读 0赞

## [1082 Read Number in Chinese (25 分)][1082 Read Number in Chinese _25] ##

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output `Fu` first if it is negative. For example, -123456789 is read as `Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu`. Note: zero (`ling`) must be handled correctly according to the Chinese tradition. For example, 100800 is `yi Shi Wan ling ba Bai`.

#### Input Specification: ####

Each input file contains one test case, which gives an integer with no more than 9 digits.

#### Output Specification: ####

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

#### Sample Input 1: ####

-123456789

#### Sample Output 1: ####

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

#### Sample Input 2: ####

100800

#### Sample Output 2: ####

yi Shi Wan ling ba Bai

我第一次写的时候，只得了16分，有两个测试点没过（说是格式错误），后来，又有其他事，就一直耽误了，今天又看了看。

PS：我的代码虽然过了，但是我自己发现了bug ，如：输入0000000 输出 Wan ，如果有哪位大神，有很简短的代码，请评论区留链接。

#include<iostream>
    #include<cstring>
    #include<cstdio>
    using namespace std;
    int main()
    {
    	string a[10]={"","yi","er","san","si","wu","liu","qi","ba","jiu"};
    	string b[4]={"","Shi","Bai","Qian"};
    	string c;
    	int i,j,q=0,len,s_l,f,flag=0;
    	cin>>c;
    	len=c.length();
    	if(c[0]=='-')
    	{
    		q=1;
    		f=0;
    		s_l=len-1;
    		cout<<"Fu";
    	}
    	else
    	{
    		q=0;
    		f=1;
    		s_l=len;
    	}
    	if(len==1&&c[q]=='0')
    	{
    		cout<<"ling"<<endl;
    		return 0;
    	} 
    	
    	for(;q<len;q++)
    	{
    		if(c[q]-'0'!=0)
    		{
    			if(c[0]!='-'&&!flag)
    			{
    				flag=1;
    			}
    			else
    			if(c[0]=='-'&&!flag)
    			{
    				cout<<" ";
    				flag=1;
    			}
    			else
    			if(flag)
    			cout<<" ";
    			cout<<a[c[q]-'0'];
    			if((s_l-q-f)%4!=0)
    			{
    				cout<<" ";
    				cout<<b[(s_l-q-f)%4];
    			}
    		}
    		if((s_l-q-f)%4==0)
    		{
    			if((s_l-q-f)/4==2)
    			{
    				cout<<" Yi";
    			}
    			
    			if((s_l-q-f)/4==1)
    			{
    				cout<<" Wan";
    			}
    			
    		}
    		if(c[q]-'0'==0&&c[q+1]-'0'!=0&&q+1<len)
    		{
    			cout<<" ling";
    		}
    	}
    	cout<<endl;
    	return 0;
    }

别人的代码：

#include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    char num[10][5] = {
        "ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"
    };
    char wei[5][5] = {"Shi", "Bai", "Qian", "Wan", "Yi"};
    int main() {
        char str[15];
        scanf("%s", str);
        int len = strlen(str);
        int left = 0, right = len - 1;
        if(str[0] == '-') {
            printf("Fu");
            left++;
        }
        while(left + 4 <= right) {
            right -= 4;
        }
        while(left < len) {
            bool flag = false;
            bool isPrint = false;
            while(left <= right) {
                if(left > 0 && str[left] == '0') {
                    flag = true;
                } else {
                    if(flag) {
                        printf(" ling");
                        flag = false;
                    }
                    if(left > 0) {
                        printf(" ");
                    }
                    printf("%s", num[str[left] - '0']);
                    isPrint = true;
                    if(left != right) {
                        printf(" %s", wei[right - left - 1]);
                    }
                }
                left++;
            }
            if(isPrint && right != len - 1) {
                printf(" %s", wei[(len - 1 - right) / 4 + 2]);
            }
            right += 4;
        }
        return 0;
    }

[1082 Read Number in Chinese _25]: https://pintia.cn/problem-sets/994805342720868352/problems/994805385053978624