1082. Read Number in Chinese (25)

╰半橙微兮° 2022-05-29 13:46 137阅读 0赞

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output "Fu" first if it is negative. For example, -123456789 is read as "Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu". Note: zero ("ling") must be handled correctly according to the Chinese tradition. For example, 100800 is "yi Shi Wan ling ba Bai".

**Input Specification:**

Each input file contains one test case, which gives an integer with no more than 9 digits.

**Output Specification:**

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

**Sample Input 1:**

-123456789

**Sample Output 1:**

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

**Sample Input 2:**

100800

**Sample Output 2:**

yi Shi Wan ling ba Bai

--------------------

题目大意：

代码：

#include<stdio.h>
    #include<stdlib.h>
    char a[10][5]={"Shi","Bai","Qian","Wan","Shi","Bai","Qian","Yi"};
    char c[11][5]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
    int b[15],m,flag=0;
    int main()
    {
        int i,j,n,k,t,l=0;
        scanf("%d",&n);
        m=abs(n);
        if(n<0)
        {
            printf("Fu ");
        }
        if(m==0)
        {
            printf("ling");
        }
        while(m>0)
        {
            b[l++]=m%10;
            m/=10;
        }
        for(i=l-1;i>=0;i--)
        {
            for(j=i;j>=0;j--)
                    if(b[j]!=0)
                    break;
                if(j<0)
                    break;
            if(b[i]==0)
            {
                if(i>3)
                {
                   for(j=i;j>3;j--)
                   {
                       if(b[j]!=0)
                        break;
                   }
                   i=j+1;
                   if(j<=3)
                   {
                      printf(" Wan");
                   }
                   else
                   {
                       printf(" ling");
                   }
                }
                else
                {
                    for(j=i;j>=0;j--)
                    {
                        if(b[j]!=0)
                        {
                            break;
                        }
                    }
                    if(j>=0)
                    {
    
                      printf(" ling");
                    }
                    i=j+1;
                }
                continue;
            }
            if(i==l-1)
            {
                if(i-1>=0)
                printf("%s %s",c[b[i]],a[i-1]);
                else
                printf("%s",c[b[i]]);
            }
            else
            {
                if(i-1>=0)
                printf(" %s %s",c[b[i]],a[i-1]);
                else
                printf(" %s",c[b[i]]);
            }
        }
        return 0;
    }