LeetCode | 1385. Find the Distance Value Between Two Arrays两个数组间的距离值【Python】

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> LeetCode 1385. Find the Distance Value Between Two Arrays两个数组间的距离值【Easy】【Python】【暴力】

### Problem ###

[LeetCode][]

Given two integer arrays `arr1` and `arr2`, and the integer `d`, *return the distance value between the two arrays*.

The distance value is defined as the number of elements `arr1[i]` such that there is not any element `arr2[j]` where `|arr1[i]-arr2[j]| <= d`.

**Example 1:**

Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
    Output: 2
    Explanation: 
    For arr1[0]=4 we have: 
    |4-10|=6 > d=2 
    |4-9|=5 > d=2 
    |4-1|=3 > d=2 
    |4-8|=4 > d=2 
    For arr1[1]=5 we have: 
    |5-10|=5 > d=2 
    |5-9|=4 > d=2 
    |5-1|=4 > d=2 
    |5-8|=3 > d=2
    For arr1[2]=8 we have:
    |8-10|=2 <= d=2
    |8-9|=1 <= d=2
    |8-1|=7 > d=2
    |8-8|=0 <= d=2

**Example 2:**

Input: arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
    Output: 2

**Example 3:**

Input: arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
    Output: 1

**Constraints:**

*  `1 <= arr1.length, arr2.length <= 500`
 *  `-10^3 <= arr1[i], arr2[j] <= 10^3`
 *  `0 <= d <= 100`

### 问题 ###

[力扣][Link 1]

给你两个整数数组 arr1 ， arr2 和一个整数 d ，请你返回两个数组之间的 **距离值** 。

「**距离值**」 定义为符合此描述的元素数目：对于元素 arr1\[i\] ，不存在任何元素 arr2\[j\] 满足 |arr1\[i\]-arr2\[j\]| <= d 。

**示例 1：**

输入：arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
    输出：2
    解释：
    对于 arr1[0]=4 我们有：
    |4-10|=6 > d=2 
    |4-9|=5 > d=2 
    |4-1|=3 > d=2 
    |4-8|=4 > d=2 
    对于 arr1[1]=5 我们有：
    |5-10|=5 > d=2 
    |5-9|=4 > d=2 
    |5-1|=4 > d=2 
    |5-8|=3 > d=2
    对于 arr1[2]=8 我们有：
    |8-10|=2 <= d=2
    |8-9|=1 <= d=2
    |8-1|=7 > d=2
    |8-8|=0 <= d=2

**示例 2：**

输入：arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
    输出：2

**示例 3：**

输入：arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
    输出：1

**提示：**

*  `1 <= arr1.length, arr2.length <= 500`
 *  `-10^3 <= arr1[i], arr2[j] <= 10^3`
 *  `0 <= d <= 100`

### 思路 ###

**暴力**

**时间复杂度:** O(n^2)  
**空间复杂度:** O(1)

##### Python3代码 #####

from typing import List
    
    class Solution:
        def findTheDistanceValue(self, arr1: List[int], arr2: List[int], d: int) -> int:
            # solution one: 暴力
            res = 0
            for x in arr1:
                cnt = 0
                for y in arr2:
                    if abs(x-y) <= d:
                        break
                    else:
                        cnt += 1
                    if cnt == len(arr2):
                        res += 1
            return res
    
            # solution two: 一行代码
            return sum(all(abs(a1 - a2) > d for a2 in arr2) for a1 in arr1)

### GitHub链接 ###

[Python][]

[LeetCode]: https://leetcode.com/problems/find-the-distance-value-between-two-arrays/
[Link 1]: https://leetcode-cn.com/problems/find-the-distance-value-between-two-arrays/
[Python]: https://github.com/Wonz5130/LeetCode-Solutions/blob/master/solutions/1385-Find-the-Distance-Value-Between-Two-Arrays/1385.py