c++: 复数类

叁歲伎倆 2023-06-12 06:24 9阅读 0赞

### c++: 复数类 ###

*  输出

#include<iostream>
    using namespace std;
    
    class complex
    { 
    private:
       double real;
       double imaginary ;
    public:
        complex():real(0),imaginary(0){ }
        complex(double x,double y):real(x),imaginary(y){ }
        void operator = (const complex&c){ 
            real=c.real;
            imaginary=c.imaginary;
        }
        ~complex(){ }
        complex operator- () { 
            return complex(-real,-imaginary);
        }
        complex operator+(const complex&c){ 
            complex com;
            com.real=real+c.real;
            com.imaginary=imaginary+c.imaginary;
            return com;
        }// 定义复数加法
        complex operator-(const complex&c){ 
            complex com;
            com.real = real - c.real;
            com.imaginary = imaginary - c.imaginary;
            return com;
        }//定义复数减法
        complex operator*(const complex&c){ 
            complex com ;
            com.real = real*c.real - imaginary*c.imaginary;
            com.imaginary = real*c.imaginary + imaginary*c.real;
            return com;
        }// 定义复数除法
        complex operator/(const complex&c){ 
            complex com;
            double denominator = c.real*c.real + c.imaginary*c.imaginary;
            com.real = (real*c.real + imaginary*c.imaginary)/denominator;
            com.imaginary = (imaginary*c.real-real*c.imaginary)/denominator;
            return com;
        }
    
        /*习惯上人们是使用 cin>> 和 cout<< 的，得使用友元函数来重载运算符， 如果使用成员函数来重载会出现 d1<<cout; 这种不自然的代码*/
        friend ostream &operator<<( ostream &output, const complex &c ){  
             output <<"( "<< c.real<<" ," <<c.imaginary<<" i )";
             return output;            
        }//输出运算符重载
        friend istream &operator>>( istream  &input, complex &c ){  
             input >> c.real >> c.imaginary;
             return input;            
        }//输入运算符重载
    };
    
    int main(){ 
        complex a(4,6),b(2,-1);
        cout<<a<<" + "<<b<<" = "<<a+b<<endl;
        cout<<a<<" - "<<b<<" = "<<a-b<<endl;
        cout<<a<<" * "<<b<<" = "<<a*b<<endl;
        cout<<a<<" / "<<b<<" = "<<a/b<<endl;
        return 0;
    }

# 输出 #

( 4 ,6 i ) + ( 2 ,-1 i ) = ( 6 ,5 i )
    ( 4 ,6 i ) - ( 2 ,-1 i ) = ( 2 ,7 i )
    ( 4 ,6 i ) * ( 2 ,-1 i ) = ( 14 ,8 i )
    ( 4 ,6 i ) / ( 2 ,-1 i ) = ( 0.4 ,3.2 i )