Compare Strings by Frequency of the Smallest Character（C++比较字符串最小字母出现频次）

超、凢脫俗 2023-01-13 14:00 97阅读 0赞

解题思路：

（1）排序，双指针

class Solution {
    private:
        int count=0;
    public:
        int helper(string &s) {
            map<char,int> mp;
            for(int i=0;i<s.length();i++) {
                mp[s[i]]++;
            }
            return mp.begin()->second;
        }
        vector<int> numSmallerByFrequency(vector<string>& queries, vector<string>& words) {
            vector<int> v(queries.size(),0),v2;
            vector<pair<int,int>> v1;
            for(int i=0;i<queries.size();i++) {
                v1.push_back({helper(queries[i]),i});
            }
            for(int i=0;i<words.size();i++) {
                v2.push_back(helper(words[i]));
            }
            
            auto comp=[&](const pair<int,int> &a,const pair<int,int> &b){
                if(a.first<b.first) return true;
                else return false;
            };
            sort(v1.begin(),v1.end(),comp);
            sort(v2.begin(),v2.end());
            
            int i=0,j=0;
            while(i<v1.size() && j<v2.size()) {
                if(v1[i].first<v2[j]) {
                    count=v2.size()-j;
                    v[v1[i].second]=count;
                    i++;
                } else j++;
            }
            return v;
        }
    };