Leetcode 1170. 比较字符串最小字母出现频次（DAY 180）---- 二分查找学习期

╰+哭是因爲堅強的太久メ 2022-09-14 06:25 162阅读 0赞

### 文章目录 ###

*   *  原题题目
     *  代码实现（首刷自解）

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## 原题题目 ##

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![在这里插入图片描述][watermark_type_ZHJvaWRzYW5zZmFsbGJhY2s_shadow_50_text_Q1NETiBATG92ZSA2_size_20_color_FFFFFF_t_70_g_se_x_16]

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## 代码实现（首刷自解） ##

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class Solution { 
    public:
        vector<int> numSmallerByFrequency(vector<string>& queries, vector<string>& words) { 
            vector<int> tmpcnt(26,0),tmp(tmpcnt),words_cnt,ret;
            for(int i=0;i<words.size();++i)
            { 
                tmpcnt = tmp;
                int min_num = 0;
                char min_chr = 'z';
                for(const auto& chr:words[i])
                { 
                    ++tmpcnt[chr-'a'];
                    min_chr = min(chr,min_chr);
                    if(chr == min_chr)  min_num = tmpcnt[chr-'a'];
                }
                words_cnt.emplace_back(min_num);
            }
            sort(words_cnt.begin(),words_cnt.end());
    
            for(int i=0;i<queries.size();++i)
            { 
                tmpcnt = tmp;
                int min_num = 0;
                char min_chr = 'z';
                for(const auto& chr:queries[i])
                { 
                    ++tmpcnt[chr-'a'];
                    min_chr = min(chr,min_chr);
                    if(chr == min_chr)  min_num = tmpcnt[chr-'a'];
                }
                auto iter = upper_bound(words_cnt.begin(),words_cnt.end(),min_num);
                ret.emplace_back(words_cnt.end()-iter);
            }
            return ret;
        }
    };

[watermark_type_ZHJvaWRzYW5zZmFsbGJhY2s_shadow_50_text_Q1NETiBATG92ZSA2_size_20_color_FFFFFF_t_70_g_se_x_16]: /images/20220828/51832110d0d74de2a0dd611466c529dd.png