lua 二进制字节与int相互转换

╰半橙微兮° 2022-06-10 08:52 352阅读 0赞

看过我转载的[http://blog.csdn.net/u013654125/article/details/73381633][http_blog.csdn.net_u013654125_article_details_73381633]的同学，如果需要用lua把自定义的二进制数据和protobuf结合成新的数据传给服务器，可以看下面的代码：由于lua传递的数据是字符串，所以需要把字符串转成ascii串，这样才能解析出来。

代码：

--  工具类
    cc.exports.Utils = class("Utils")
    
    -- 下面的二进制=ascii
    
    -- 二进制转int
    function Utils:bufToInt32(num1, num2, num3, num4)
        local num = 0;
        num = num + self:leftShift(num1, 24);
        num = num + self:leftShift(num2, 16);
        num = num + self:leftShift(num3, 8);
        num = num + num4;
        return num;
    end
    
    -- int转二进制
    function Utils:int32ToBufStr(num)
        local str = "";
        str = str .. self:numToAscii(self:rightShift(num, 24));
        str = str .. self:numToAscii(self:rightShift(num, 16));
        str = str .. self:numToAscii(self:rightShift(num, 8));
        str = str .. self:numToAscii(num);
        return str;
    end
    
    -- 二进制转shot
    function Utils:bufToInt16(num1, num2)
        local num = 0;
        num = num + self:leftShift(num1, 8);
        num = num + num2;
        return num;
    end
    
    -- shot转二进制
    function Utils:int16ToBufStr(num)
        local str = "";
        str = str .. self:numToAscii(self:rightShift(num, 8));
        str = str .. self:numToAscii(num);
        return str;
    end
    
    
    -- 左移
    function Utils:leftShift(num, shift)
        return math.floor(num * (2 ^ shift));
    end
    
    -- 右移
    function Utils:rightShift(num, shift)
        return math.floor(num / (2 ^ shift));
    end
    
    -- 转成Ascii
    function Utils:numToAscii(num)
        num = num % 256;
        return string.char(num);
    end

[http_blog.csdn.net_u013654125_article_details_73381633]: http://blog.csdn.net/u013654125/article/details/73381633