Java中String与二进制码的相互转换

小鱼儿 2022-05-20 08:54 669阅读 0赞

把字符串转成二进制码

public class stringTest {
        public static void main(String[] args) {
            String str = "abc";
            String binary = toBinary(str);
            System.out.println(binary);
        }
    
        public static String toBinary(String str){
            //把字符串转成字符数组
            char[] strChar=str.toCharArray();
            String result="";
            for(int i=0;i<strChar.length;i++){
                //toBinaryString(int i)返回变量的二进制表示的字符串
                //toHexString(int i) 八进制
                //toOctalString(int i) 十六进制
                result +=Integer.toBinaryString(strChar[i])+ " ";
            }
            return result;
        }
    }

结果：abc–>1100001 1100010 1100011

将二进制码转成字符串

public class stringTest {
        public static void main(String[] args) {
            String binary = "1100001 1100010 1100011";      
            System.out.println(toString(binary));
        }
    
        public static String toString(String binary) {
             String[] tempStr=binary.split(" ");
                char[] tempChar=new char[tempStr.length];
                for(int i=0;i<tempStr.length;i++) {
                   tempChar[i]=BinstrToChar(tempStr[i]);
                }
                return String.valueOf(tempChar);
        }
    
    
        //将二进制字符串转换成int数组
        public static int[] BinstrToIntArray(String binStr) {       
            char[] temp=binStr.toCharArray();
            int[] result=new int[temp.length];   
            for(int i=0;i<temp.length;i++) {
                result[i]=temp[i]-48;
            }
            return result;
        }
    
    
        //将二进制转换成字符
        public static char BinstrToChar(String binStr){
            int[] temp=BinstrToIntArray(binStr);
            int sum=0;
            for(int i=0; i<temp.length;i++){
                sum +=temp[temp.length-1-i]<<i;
            }   
            return (char)sum;
       }
    }

结果：1100001 1100010 1100011 –>abc

java源码Integer类：[https://blog.csdn.net/u013190513/article/details/70216730][https_blog.csdn.net_u013190513_article_details_70216730]

[https_blog.csdn.net_u013190513_article_details_70216730]: https://blog.csdn.net/u013190513/article/details/70216730