leetcode 462. Minimum Moves to Equal Array Elements II 换一个角度思考问题 + 寻找中位数

Dear 丶 2022-06-02 23:36 145阅读 0赞

Given a non-empty integer array, find the minimum number of moves required to make all array elements equal, where a move is incrementing a selected element by 1 or decrementing a selected element by 1.

You may assume the array’s length is at most 10,000.

Example:

Input:  
\[1,2,3\]

Output:  
2

Explanation:  
Only two moves are needed (remember each move increments or decrements one element):

\[1,2,3\] => \[2,2,3\] => \[2,2,2\]

本题是上一道题[leetcode 453. Minimum Moves to Equal Array Elements][] 的变种，

其实第一种方法最棒，很奇妙的想法。

参考这个链接[\[LeetCode\] Minimum Moves to Equal Array Elements II 最少移动次数使数组元素相等之二  
][LeetCode_ Minimum Moves to Equal Array Elements II _]

代码如下：

#include <iostream>
    #include <vector>
    #include <map>
    #include <set>
    #include <queue>
    #include <stack>
    #include <string>
    #include <climits>
    #include <algorithm>
    #include <sstream>
    #include <functional>
    #include <bitset>
    #include <cmath>
    
    using namespace std;
    
    class Solution 
    {
    public:
        int minMoves2(vector<int>& nums) 
        {
            sort(nums.begin(), nums.end());
            int res = 0, i = 0, j = (int)nums.size() - 1;
            while (i < j)
            {
                res += nums[j] - nums[i];
                j--;
                i++;
            }
            return res;
        }
    
        int minMoves2ByMidean(vector<int>& nums) 
        {
            sort(nums.begin(), nums.end());
            int res = 0, mid = nums[nums.size() / 2];
            for (int num : nums)
                res += abs(num - mid);
            return res;
        }
    };

[leetcode 453. Minimum Moves to Equal Array Elements]: http://blog.csdn.net/jackzhang_123/article/details/78760254
[LeetCode_ Minimum Moves to Equal Array Elements II _]: https://www.cnblogs.com/grandyang/p/6089060.html