1077. Kuchiguse (20)

偏执的太偏执、 2022-05-30 02:29 181阅读 0赞

The Japanese language is notorious for its sentence ending particles. Personal preference of such particles can be considered as a reflection of the speaker's personality. Such a preference is called "Kuchiguse" and is often exaggerated artistically in Anime and Manga. For example, the artificial sentence ending particle "nyan~" is often used as a stereotype for characters with a cat-like personality:

Itai nyan~ (It hurts, nyan~)Ninjin wa iyada nyan~ (I hate carrots, nyan~)

Now given a few lines spoken by the same character, can you find her Kuchiguse?

**Input Specification:**

Each input file contains one test case. For each case, the first line is an integer N (2<=N<=100). Following are N file lines of 0~256 (inclusive) characters in length, each representing a character's spoken line. The spoken lines are case sensitive.

**Output Specification:**

For each test case, print in one line the kuchiguse of the character, i.e., the longest common suffix of all N lines. If there is no such suffix, write "nai".

**Sample Input 1:**

3
    Itai nyan~
    Ninjin wa iyadanyan~
    uhhh nyan~

**Sample Output 1:**

nyan~

**Sample Input 2:**

3
    Itai!
    Ninjinnwaiyada T_T
    T_T

**Sample Output 2:**

nai

--------------------

题目大意：

代码：

#include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    #include<string>
    using namespace std;
    char *suffix,input[300],tmp[300];
    int main()
    {
        int i,j,n,m,k,t,tmplen,inputlen;
        scanf("%d",&n);
        getchar();
        gets(tmp);
        m=strlen(tmp);
        suffix=tmp;
        for(i=1;i<n;i++)
        {
            //printf("1\n");
            gets(input);
            tmplen=m-1;
            inputlen=strlen(input)-1;
            while(input[inputlen]==tmp[tmplen])
            {
                inputlen--;
                tmplen--;
                //printf("2");
            }
            if(tmplen==m-1)
            {
                suffix="nai";
                break;
            }
            if(strlen(suffix)>m-tmplen-1)
            {
                suffix=tmp+tmplen+1;
            }
        }
        printf("%s\n",suffix);
        return 0;
    }