A. Another One Bites The Dust

矫情吗；* 2022-01-23 09:59 164阅读 0赞

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Let's call a string good if and only if it consists of only two types of letters — 'a' and 'b' and every two consecutive letters are distinct. For example "baba" and "aba" are good strings and "abb" is a bad string.

You have aa strings "a", bb strings "b" and cc strings "ab". You want to choose some subset of these strings and concatenate them in any arbitrarily order.

What is the length of the longest good string you can obtain this way?

Input

The first line contains three positive integers aa, bb, cc (1≤a,b,c≤1091≤a,b,c≤109) — the number of strings "a", "b" and "ab" respectively.

Output

Print a single number — the maximum possible length of the good string you can obtain.

Examples

input

Copy

1 1 1

output

Copy

input

Copy

2 1 2

output

Copy

input

Copy

3 5 2

output

Copy

input

Copy

2 2 1

output

Copy

input

Copy

1000000000 1000000000 1000000000

output

Copy

4000000000

Note

In the first example the optimal string is "baba".

In the second example the optimal string is "abababa".

In the third example the optimal string is "bababababab".

In the fourth example the optimal string is "ababab".

**题意：输入a,b,c表示字符a的个数，字符b的个数，字符ab的个数，然后组成一个字符串，相邻的两个字符不能一样，输出能够得到的最长字符串的长度。**

**题解：贪心 规律题   如果a,b的个数相等那就是c\*2+a+b就是最大长度，不相等就是c\*2+min(a,b)+1**

c++：

#include<bits/stdc++.h>
    using namespace std;
    int main()
    {
        long long a,b,c;
        cin>>a>>b>>c;
        cout<<(a==b?(a+c)*2:(min(a,b)+c)*2+1)<<endl;
        return 0;
    }

python：

a,b,c=map(int,input().split())
    print(min(a,b)*2+c*2+(a!=b))