Python方式实现射后不管导弹的简易制导系统

阳光穿透心脏的1/2处 2024-03-23 22:30 47阅读 0赞

**1** **问题**

对QN-506上的S570智能反坦克制导导弹的射后不管产生了浓厚的兴趣，想用Python简易还原一下。

**2** **方法**

1.  之前查阅资料时了解到使用pygame库制作的贪吃蛇，是否有一种方法能让“贪吃蛇”一直跟着鼠标走呢？
    
    鼠标模拟行进中的坦克，“蛇头”模拟S570巡飞弹;
2.  先把pygame框架搭好，把导弹的基本参数定义好;
3.  导弹是会拐弯的，但它不是质点，所以引入了一张矩形图片，还要把它的旋转效果做出来。
    
    但就在我认知范围内在pygame中做出旋转效果并不容易;
4.  ![49cd71f778ae5114fd955f931fe6d9c5.jpeg][]![8b55d6833d7838e44dcaca6972673e99.jpeg][]
5.  查阅相关资料后了解到可以让图片变形实现旋转效果，可以用以下代码实现：
    
    screen.blit(missiled,(x1-width+(x1-C\[0\]),y1-height/2+(y1-C\[1\])));

通过实验、实践等证明提出的方法是有效的，是能够解决开头提出的问题。

代码清单 1

<table> 
 <tbody> 
 <tr> 
 <td>import pygame,sys from math import * pygame.init() font1=pygame.font.SysFont('microsoftyaheimicrosoftyaheiui',23) textc=font1.render('T',True,(250,0,0)) screen=pygame.display.set_mode((800,700),0,32) missile=pygame.image.load('missile.png').convert_alpha() height=missile.get_height() width=missile.get_width() pygame.mouse.set_visible(0) x1,y1=100,600 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; #导弹的初始发射位置 velocity=800 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;#导弹速度 time=1/1000 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; #每个时间片的长度 clock=pygame.time.Clock() A=() B=() C=() while True: &nbsp; &nbsp;for event in pygame.event.get(): &nbsp; &nbsp; &nbsp; &nbsp;if event.type==pygame.QUIT: &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;sys.exit() &nbsp; &nbsp;clock.tick(300) &nbsp; &nbsp;x,y=pygame.mouse.get_pos() &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;#获取鼠标位置，鼠标就是需要打击的目标 &nbsp; &nbsp;distance=sqrt(pow(x1-x,2)+pow(y1-y,2)) &nbsp; &nbsp; &nbsp;#两点距离公式 &nbsp; &nbsp;section=velocity*time &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; #每个时间片需要移动的距离 &nbsp; &nbsp;sina=(y1-y)/distance &nbsp; &nbsp;cosa=(x-x1)/distance &nbsp; &nbsp;angle=atan2(y-y1,x-x1) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;#两点间线段的弧度值 &nbsp; &nbsp;fangle=degrees(angle) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; #弧度转角度 &nbsp; &nbsp;x1,y1=(x1+section*cosa,y1-section*sina) &nbsp; &nbsp;missiled=pygame.transform.rotate(missile,-(fangle)) &nbsp; &nbsp;if 0&lt;=-fangle&lt;=90: &nbsp; &nbsp; &nbsp; &nbsp;A=(width*cosa+x1-width,y1-height/2) &nbsp; &nbsp; &nbsp; &nbsp;B=(A[0]+height*sina,A[1]+height*cosa) &nbsp; &nbsp;if 90&lt;-fangle&lt;=180: &nbsp; &nbsp; &nbsp; &nbsp;A = (x1 - width, y1 - height/2+height*(-cosa)) &nbsp; &nbsp; &nbsp; &nbsp;B = (x1 - width+height*sina, y1 - height/2) &nbsp; &nbsp;if -90&lt;=-fangle&lt;0: &nbsp; &nbsp; &nbsp; &nbsp;A = (x1 - width+missiled.get_width(), y1 - height/2+missiled.get_height()-height*cosa) &nbsp; &nbsp; &nbsp; &nbsp;B = (A[0]+height*sina, y1 - height/2+missiled.get_height()) &nbsp; &nbsp;if -180&lt;-fangle&lt;-90: &nbsp; &nbsp; &nbsp; &nbsp;A = (x1-width-height*sina, y1 - height/2+missiled.get_height()) &nbsp; &nbsp; &nbsp; &nbsp;B = (x1 - width,A[1]+height*cosa ) &nbsp; &nbsp;C = ((A[0] + B[0]) / 2, (A[1] + B[1]) / 2) &nbsp; &nbsp;screen.fill((0,0,0)) &nbsp; &nbsp;screen.blit(missiled, (x1-width+(x1-C[0]),y1-height/2+(y1-C[1]))) &nbsp; &nbsp;screen.blit(textc, (x,y)) #鼠标用一个红色T代替 pygame.display.update() <img src="https://img-blog.csdnimg.cn/img_convert/140f66917ea7bd400ab096038203744d.png" alt="140f66917ea7bd400ab096038203744d.png">附件：代码中的missile.png文件</td> 
 </tr> 
 </tbody> 
</table>

**3** **结语**

针对在pygame中实现图片旋转的问题，提出显示图片时将其移动的方法，通过实机实验，证明该方法是有效的。未来还可以加入导弹撞击到“T”时的爆炸效果。

[49cd71f778ae5114fd955f931fe6d9c5.jpeg]: https://img-blog.csdnimg.cn/img_convert/49cd71f778ae5114fd955f931fe6d9c5.jpeg
[8b55d6833d7838e44dcaca6972673e99.jpeg]: https://image.dandelioncloud.cn/pgy_files/images/2024/03/14/c0fdb1222a91466f8f0ded69ae615d45.png