链表——两数相加

柔光的暖阳◎ 2024-02-19 15:15 66阅读 0赞

精简之后

class Solution {
        public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
            //设置进位位,当前结果值位，设置当前节点
            int high=0;
            int nowvalue=0;
            ListNode now1=l1,now2=l2;
            nowvalue=now1.val+now2.val;
            high=nowvalue/10;
            nowvalue%=10;
            ListNode listnew=new ListNode(nowvalue),nodenow=listnew;
            now1=now1.next;
            now2=now2.next;
            //获取两个链表中对应项的值
            while(now1!=null||now2!=null||high==1){
                //判空，相加，并判断是否超过十，超过则进位位置一，或者直接新建节点，作为新链表尾节点
                if(now1!=null&&now2!=null){
                    nowvalue=now1.val+now2.val+high;
                    now1=now1.next;
                    now2=now2.next;
                }else if(now1!=null){
                    nowvalue=now1.val+high;
                    now1=now1.next;
                }else if(now2!=null){
                    nowvalue=now2.val+high;
                    now2=now2.next;
                }else if(high==1){
                    nowvalue=1;
                    high=0;
                }
                high=nowvalue/10;
                nowvalue%=10;
                while(nodenow.next!=null)nodenow=nodenow.next;
                nodenow.next=new ListNode(nowvalue);
            }
            return listnew;
        }
    }

精简之前

/**
     * Definition for singly-linked list.
     * public class ListNode {
     *     int val;
     *     ListNode next;
     *     ListNode(int x) { val = x; }
     * }
     */
    class Solution {
        public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
            //设置进位位,当前结果值位，设置当前节点
            int high=0;
            int nowvalue=0;
            ListNode now1=l1;
            ListNode now2=l2;
            nowvalue=now1.val+now2.val;
            if(nowvalue>=10){
                nowvalue%=10;
                high=1;
            }
            ListNode listnew=new ListNode(nowvalue);
            ListNode nodenow=listnew;
            now1=now1.next;
            now2=now2.next;
            //获取两个链表中对应项的值
            while(now1!=null||now2!=null||high==1){
                //判空，相加，并判断是否超过十，超过则进位位置一，或者直接新建节点，作为新链表尾节点
                if(now1!=null&&now2!=null){
                    nowvalue=now1.val+now2.val+high;
                    high=0;
                    if(nowvalue>=10){
                        nowvalue%=10;
                        high=1;
                    }else{
                        high=0;
                    }
                    now1=now1.next;
                    now2=now2.next;
                }else if(now1!=null){
                    nowvalue=now1.val+high;
                    high=0;
                    if(nowvalue>=10){
                        high=1;
                        nowvalue%=10;
                    }
                    now1=now1.next;
                }else if(now2!=null){
                    nowvalue=now2.val+high;
                    high=0;
                    if(nowvalue>=10){
                        high=1;
                        nowvalue%=10;
                    }
                    now2=now2.next;
                }else if(high==1){
                    nowvalue=1;
                    high=0;
                }
                while(nodenow.next!=null)nodenow=nodenow.next;
                nodenow.next=new ListNode(nowvalue);
            }
            return listnew;
        }
    }