一个Servlet来替代多个Servlet

深碍√TFBOYSˉ_ 2024-02-17 16:51 57阅读 0赞

一、web.xml配置文件

<servlet>
        <description>This is the description of my J2EE component</description>
        <display-name>This is the display name of my J2EE component</display-name>
        <servlet-name>AllServlet</servlet-name>
        <servlet-class>com.hlx.servlet.AllServlet</servlet-class>
      </servlet>
    
      <servlet-mapping>
        <servlet-name>AllServlet</servlet-name>
        <url-pattern>/my/*</url-pattern>
      </servlet-mapping>

二、JSP页面

1)登录页面

2)注册页面

3)添加页面

三、Servlet页面

public void doPost(HttpServletRequest request, HttpServletResponse response)
    			throws ServletException, IOException {
    
    		//处理响应编码
    		response.setContentType("text/html;charset=utf-8");
    		PrintWriter out = response.getWriter();
    	    
    		//获得请求路径
    		String path  = request.getRequestURI();
    		System.out.println(path);
    		//截取路径
    		///one/my/login.do  取出名称（reg,add...)
    		String action = path.substring(path.lastIndexOf("/")+1, path.indexOf("."));
    		
    		System.out.println(action);
    		
    		//判断各个action操作
    		if("reg".equals(action)){  //注册
    			out.println("reg page");
    		}else if("login".equals(action)){ //登录
    			out.println("login page");
    		}else if("add".equals(action)){  //添加
    			out.println("add page");
    		}
    		
    	
    		out.flush();
    		out.close();
    	}

总之：解决方法有很多，只不过是其中的一种!