牛客网语法篇刷题(C语言) — 分支控制

ゝ一纸荒年。 2023-10-12 15:11 81阅读 0赞

> ![5589644344484613bca3cbd6c367b49c.png][]
> 
> **作者主页：**paper jie的博客\_CSDN博客-C语言,算法详解领域博主
> 
> **本文作者：**大家好，我是paper jie，感谢你阅读本文，欢迎一建三连哦。
> 
> **本文录入于**《C语言-语法篇》专栏，本专栏是针对于大学生，编程小白精心打造的。笔者用重金(时间和精力)打造，将C语言基础知识一网打尽，希望可以帮到读者们哦。
> 
> **其他专栏：**《C语言》《算法详解》《C语言系统详解》
> 
> **内容分享：**本期将用C语言对牛客网刷题的语法篇分支控制行进行具体讲解，各位看官姥爷快搬好小板凳坐好叭。
> 
>  \-------- 不要998，不要98，只要一键三连，三连买不了吃亏，买不了上当

**目录**

题目链接

第一题

第二题

第三题

第四题

第五题

第六题

第七题

第八题

第九题

第十题

第十一题

第十二题

第十三题

第十四题

第十五题

第十六题

第十七题

第十八题

--------------------

# 题目链接 #

[四季\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com]

[健康评估\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 1]

[小乐乐找最大数\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 2]

[判断是不是字母\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 3]

[牛牛的二三七整除\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 4]

[统计数据正负个数\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 5]

[网购\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 6]

[牛牛的快递\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 7]

[牛牛的通勤\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 8]

[牛牛的金币\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 9]

[牛牛的一周\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 10]

[HTTP状态码\_牛客题霸\_牛客网 (nowcoder.com)][HTTP_ _nowcoder.com]

[计算单位阶跃函数\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 11]

[三角形判断\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 12]

[牛牛的计划\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 13]

[计算一元二次方程\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 14]

[获得月份天数\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 15]

[小乐乐是否被叫家长\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 16]

[简单计算器\_牛客题霸\_牛客网 (nowcoder.com)][_nowcoder.com 17]

--------------------

# 第一题 #

![efd86c620f284d7abba85cf4ae5caf20.png][]

#include <stdio.h>
    
    int main()
    {
        int n = 0;
        scanf("%d", &n);
        //month里面就是月份
        int month = n%100;
        //使用switch语句 
        switch(month)
        {
            //3-5
            case 3:
            case 4:
            case 5:
                    printf("spring\n");
                    break;
           //6-8         
            case 6:
            case 7:
            case 8:
                    printf("summer\n");
                    break;
            //9-11
            case 9:
            case 10:
            case 11:
                    printf("autumn\n");
                    break;
            //12-2
            case 12:
            case 1:
            case 2:
                    printf("winer\n");
                    break;
            default:
            break;
        }
        return 0;
    }

# 第二题 #

![02e745d635424b7cb6d7fa6be8b21b8e.png][]

#include <stdio.h>
    
    int main()
    {   //身高体重有小数用float类型
        float height = 0.0;
        float weight = 0.0;
        //float 输入用%f
        scanf("%f%f", &weight, &height);
        //BMI 计算公式 体重/(身高^2)
        float BMI = weight/(height*height);
        //用if else 判断
        if(BMI<=23.9 && BMI>=18.5)
        printf("Normal\n");
        else
         printf("Abnormal\n");
        return 0;
    }

# 第三题 #

![9e7f9a2611464f608dc77e9352fa1617.png][]

#include <stdio.h>
    
    int main()
    {
        int a = 0;
        int b = 0;
        int c = 0;
        int d = 0;
        scanf("%d%d%d%d", &a, &b, &c, &d);
        //三目操作符：
        // a是不是大于b n 是 a n 是 b
        int n = a>b?a:b;
        //同上
        int m = c>d?c:d;
        printf("%d\n", n>m?n:m);
    }

# 第四题 #

![fdcf94229018434985db946a95fd6e93.png][]

#include <stdio.h>
    
    int main()
    {
        char n = 0;
        //多组输入
        while(scanf("%c", &n)!=EOF)
        {
            //getchar可以将回车抵消
            getchar();
            //这里是字母的ASCII码值
            if((n>=65&&n<=90)||(n>=97&&n<=122))
            {
                printf("%c is an alphabet.\n", n);
            }
            else {
            printf("%c is not an alphabet.\n", n );
            }
        }
    }

# 第五题 #

![1e8877cc8fa2486f9413fdb2fb41b389.png][]

#include <stdio.h>
    
    int main()
    {
        int a = 0;
        scanf("%d", &a);
        int i = 0;
        //将2 3 7这些除数全部放到数组中
        int arr[3] = {2,3,7};
        //计数器判断有没有能整数的元素
        int count = 0;
        //遍历数组中的元素
        for(i=0; i<3; i++)
        {
            //能整数就打印 且count加一
            if(a%arr[i]==0)
            {
                printf("%d ", arr[i]);
                count++;
            }
        }
        //如果count没变化就打印n
        if(count==0)
        {
            printf("n");
        }
        return 0;
    }

# 第六题 #

![02fe0ddeae4e43c386b5eadbdf5ebe91.png][]

#include <stdio.h>
    
    int main()
    {
        int i = 0;
        int Z = 0;
        int F = 0;
        int arr[10] = {0};
        //将输入的数放入arr数组中
        for(i=0; i<10; i++)
        {
            scanf("%d", &arr[i]);
        }
        //遍历数组
        for(i=0; i<10; i++)
        {
            //大于0 z++
            if(arr[i]>0)
            Z++;
            //小于0 f++
            else if(arr[i]<0)
            F++;
        }
        printf("positive:%d\n", Z);
        printf("negative:%d\n", F);
    }

# 第七题 #

![fc496b37ca9c46f68e640fcccde74b92.png][]

#include <stdio.h>
    
    int main()
    {
        int n = 0;
        scanf("%d", &n);
        //走路的时间
        int s1 = n;
        //打车的时间
        int s2 = n/10 + 10;
        //不能除尽再加一秒
        if(n%10!=0)
        s2+=1;
        //判断
        if(s1>s2)
        printf("v\n");
        else
         printf("w\n");
        return 0;
    }

# 第八题 #

![cd8b20b261c24647b470162d7177c76b.png][]

#include <stdio.h>
    
    //通过题意 我们知道：
    //横坐标相等 就判断纵坐标
    //纵坐标相等 就判读横坐标
    int main()
    {
        int x = 0;
        int y = 0;
        scanf("%d%d", &x, &y);
        int x1 = 0;
        int y1 = 0;
        scanf("%d%d", &x1, &y1);
        //横坐标相等
        if(x==x1)
        {
            if(y1>y)
            {
                printf("u\n");
            }
            else {
            printf("d\n");
            }
        }
        //纵坐标相等
        if(y==y1)
        {
            if(x1>x)
            {
                printf("r\n");
            }
            else {
            printf("i\n");
            }
        }
        return 0;
    }

# 第九题 #

![51c8e52f7d5246afabad92c5f8a38ad6.png][]

#include <stdio.h>
    
    int main()
    {
        int n = 0;
        scanf("%d", &n);
        //n%7 == 1 2 3 4 5 6 7 
        switch (n % 7)
        {
        case 1:
            printf("Monday\n");
            break;
        case 2:
            printf("Tuesday\n");
            break;
        case 3:
            printf("Wednesday\n");
            break;
        case 4:
            printf("Thursday\n");
            break;
        case 5:
            printf("Friday\n");
            break;
        case 6:
            printf("Saturday\n");
            break;
        case 0:
            printf("Sunday\n");
            break;
        }
        return 0;
    }

# 第十题 #

![f1c13d47f9de4ce1b8079882114d4fad.png][]

#include <stdio.h>
    
    int main()
    {
        int n = 0;
        while(scanf("%d", &n)!= EOF)
        {
            switch(n)
            {
                case 200:
                printf("OK\n");
                break;
                case 202:
                printf("Accepted\n");
                break;
                case 400:
                printf("Bad Request\n");
                break;
                case 403:
                printf("Forbidden\n");
                break;
                case 404:
                printf("Not Found\n");
                break;
                case 500:
                printf("Internal Server Error\n");
                break;
                case 502:
                printf("Bad Gateway\n");
                break;
            }
        }
        return 0;
    }

# 第十一题 #

![ce15dbb1ae9347a79c18e5adf26d323c.png][]

#include <stdio.h>
    
    int main()
    {
        int n = 0;
        //多组输入
        while(scanf("%d", &n)!=EOF)
        {
            //大于0
            if(n>0)
            printf("1\n");
            //等于0
            else if(n==0)
            printf("0.5\n");
            //小于0
            else
             printf("0");
        }
    }

# 第十二题 #

![0409117bd7334884aa39a072b30f45ab.png][]

#include <stdio.h>
    
    int main()
    {
        int a = 0;
        int b = 0;
        int c = 0;
        //多组输入
        while(scanf("%d%d%d", &a, &b, &c)!=EOF)
        {
            //两边之和大于第三边
            if(a+b>c && a+c>b && b+c>a)
            {
                //两边相等
                if(a==b || b==c || a==c)
                {
                    //三边相等
                    if(a==b&&b==c&&a==c)
                    {
                        printf("Equilateral triangle!\n");
                    }
                    else {
                    printf("Isosceles triangle!\n");
                    }
                }
                else 
                {
                    printf("Ordinary triangle!\n");
                }
            }
            else 
            {
                printf("Not a triangle!\n");
            }
        }
        return 0;
    }

# 第十三题 #

![141d430bbaf9402285910d49fda4b601.png][]

#include <stdio.h>
    
    int main()
    {
        int y1 = 0;
        int m1 = 0;
        int d1 = 0;
        int y = 0;
        int m = 0;
        int d = 0;
        //学习时间
        scanf("%d%d%d", &y, &m, &d);
        //查询时间
        scanf("%d%d%d", &y1, &m1, &d1);
        //月和天数相加 *100是为了让月份比天数大
        int a = m*100+d;
        int b = m1*100+d1;
        //比较 
        //注意： 年份大了小了其他什么变都没用
        if(y<y1)
        printf("yes\n");
        else if(y==y1)
        {
            if(b>=a)
            printf("yes\n");
            else
             printf("no\n");;
        }
        else
        printf("no\n");
        
         
    }

# 第十四题 #

![1d7a009ef89e456da1cb4ea1e145896c.png][]

#include <stdio.h>
    #include <math.h>
    
    int main()
    {
        float a = 0.0;
        float b = 0.0;
        float c = 0.0;
        //多组输入
        while(scanf("%f%f%f", &a, &b, &c)!=EOF)
        {
            //平方根
            float v = b*b - 4*a*c;
            //没有平方根
            if(a==0)
            {
                printf("Not quadratic equation\n");
            }
            else
            {
                //平方根大于0
                if(v>0)
                {
                    float x1 = ((-b)-sqrt(v))/(2*a);
                    float x2 = ((-b)+sqrt(v))/(2*a);
                    printf("x1=%.2f;x2=%.2f\n", x1, x2);
                }
                //平方根小于0
                else if(v<0)
                {
                    float n = -b/(2*a);
                    float m =sqrt(-v)/(2*a);
                    printf("x1=%.2f-%.2fi;x2=%.2f+%.2fi\n", n, m, n, m);
                }
                //平方根等于0
                //这里要注意当结果等于0时直接用-b是不行的，这样子会得到-0.00
                //所以我们要-b+0
                else {
                    if((-b+sqrt(v))==0)
                    printf("x1=x2=0.00");
                    else
                printf("x1=x2=%.2f\n", (-b+sqrt(v))/(2*a));
                }
            }
    
        }
        return 0;
    }

# 第十五题 #

![50a47c1001104db9ae45392dc82119b4.png][]

#include <stdio.h>
    
    int main()
    {
        int year = 0;
        int month = 0;
        while(scanf("%d%d", &year, &month)!=EOF)
        {
        //我们用数组放天数   1  2  3  4  5  6  7  8  9  10 11 12
            int arr[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
            //判断闰年 4年一闰 100年不闰 400年在闰
            //这时2月就是29天
            if(((year%4==0&&year%100!=0) || (year%400==0))&&month==2)
            {
                arr[month]+=1;
                printf("%d\n", arr[month]);
            }
            else {
            printf("%d\n", arr[month]);
            }
        }
        return 0;
    }

# 第十六题 #

![831ab214203c42e4b98ccd742cd1ea3d.png][]

#include <stdio.h>
    
    int main()
    {
        int math = 0;
        int chinese = 0;
        int english = 0;
        //输入
        scanf("%d%d%d", &math, &chinese, &english);
        //成绩之和
        int sum = math + chinese +english;
        //判断平均数是不是大于等于60
        if(sum/3.0<60)
        printf("YES\n");
        else
         printf("NO\n");
        return 0;
    }

# 第十七题 #

![e95c158b884441bab92290774af234fd.png][]

#include <stdio.h>
    
    int main()
    {
        //生产一个数组 存放输入的值
        char ch[20] = {0};
        //输入
        scanf("%s", ch);
        int i = 0;
        int j = 1;
        int n = 0;
        //用循环计算识别码中数字乘积之和
        for(int i = 0; i<11; i++)
        {
            if(ch[i]!='-')
            {
                n += (ch[i]-'0')*j;
                j+=1;
            }
        }
        //m是识别码
        int m = n%11;
        //判断识别码是否正确
        if(m==ch[12]-'0' ||(m==10 && ch[12]=='X'))
        {
            printf("Right\n");
        }
        //不正确
        else 
        {
            //m==10时
            if(m==10)
            {
                //用循环打印字符 最后一个不打印
                for(i=0; i<12; i++)
                {
                    printf("%c", ch[i]);
                }
                //这里打印需要的值
                printf("X");
            }
            else
            {
                 for(i=0; i<12; i++)
                {
                    printf("%c", ch[i]);
                }
                printf("%d", m);
            }
        }
    }

# 第十八题 #

![4b0c183c73694f708cb94ead736a0f67.png][]

#include <stdio.h>
    
    int main()
    {
        //用浮点数存放两个操作数
        double a = 0;
        double b = 0;
        char ch = 0;
        //多组输入
        while(scanf("%lf%c%lf", &a, &ch, &b)!=EOF)
        {
            //判断是否+-*/
            if(ch!='+'&&ch!='-'&&ch!='*'&&ch!='/')
            printf("Invalid operation!\n");
            else
             {
                //进入相应的计算
                if(ch=='+')
                printf("%.4lf+%.4lf=%.4lf\n", a, b, a+b);
                else if(ch=='-')
                printf("%.4lf-%.4lf=%.4lf\n", a, b, a-b);
                else if(ch=='*')
                printf("%.4lf*%.4lf=%.4lf\n", a, b, a*b);
                else if(ch=='/')
                {
                if(b==0.0)
                //分母为0时：
                printf("Wrong!Division by zero!\n");
                else
                printf("%.4lf/%.4lf=%.4lf\n", a, b, a/b);
                }
                
             };
        }
        return 0;
    }

--------------------

[5589644344484613bca3cbd6c367b49c.png]: https://img-blog.csdnimg.cn/5589644344484613bca3cbd6c367b49c.png
[_nowcoder.com]: https://www.nowcoder.com/practice/eaf21203b61b4a689987fdc165d00dfc?tpId=290&tqId=1189147&ru=/exam/oj&qru=/ta/beginner-programmers/question-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E8%25AF%25AD%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D290
[_nowcoder.com 1]: https://www.nowcoder.com/practice/08b28e61ff6345febf09969b3a167f7e?tpId=290&tqId=295418&ru=/exam/oj&qru=/ta/beginner-programmers/question-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E8%25AF%25AD%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D290
[_nowcoder.com 2]: https://www.nowcoder.com/practice/ae6a21920cac4f9184c8ecfcc87f89b9?tpId=290&tqId=634143&ru=/exam/oj&qru=/ta/beginner-programmers/question-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E8%25AF%25AD%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D290
[_nowcoder.com 3]: https://www.nowcoder.com/practice/91a588dd4cd244bfa616f17603ec123c?tpId=290&tqId=307550&ru=/exam/oj&qru=/ta/beginner-programmers/question-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E8%25AF%25AD%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D290
[_nowcoder.com 4]: https://www.nowcoder.com/practice/b2cf0b791245436f8f0591ae9f4c664f?tpId=290&tqId=2368199&ru=/exam/oj&qru=/ta/beginner-programmers/question-ranking&sourceUrl=%2Fexam%2Foj%3Fpage%3D1%26tab%3D%25E8%25AF%25AD%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D290
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