在 C# 中等待线程完成Task.WaitAll和Thread.Join

柔情只为你懂 2023-10-01 20:14 9阅读 0赞

1.  [Task.WaitAll()等待线程以 C\#方法结束][Task.WaitAll_ C]
2.  [Thread.Join()等待线程以 C\#方法结束][Thread.Join_ C]

本教程将向您展示如何在 C\# 中等待线程完成。

### [Task.WaitAll()等待线程以C\#方法结束][Task.WaitAll_C] ###

C\#[Task.WaitAll()方法][Task.WaitAll]用于`Task`等待类中所有对象的完成。[Task类][Task]代表 C\# 异步任务。`Task`您可以在您的类中启动一个线程并等待 C\#`Task.WaitAll()`方法完成该线程。

using System;
    using System.Threading.Tasks;
    
    namespace wait_for_thread
    {
        class Program
        {
            static void fun1()
            {
                for(int i = 0; i < 2; i++)
                {
                    Console.WriteLine("Thread 1");
                }
            }
            static void fun2()
            {
                for (int i = 0; i < 2; i++)
                {
                    Console.WriteLine("Thread 2");
                }
            }
            static void Main(string[] args)
            {
                Task thread1 = Task.Factory.StartNew(() => fun1());
                Task thread2 = Task.Factory.StartNew(() => fun2());
                Task.WaitAll(thread1, thread2);
                Console.WriteLine("The End");
            }
        }
    }

输出：

Thread 1
    Thread 1
    Thread 2
    Thread 2
    The End

在上面的代码中，我使用了 C\# 中的一个方法来等待`Task.WaitAll()`主线程中的任务`thread1`和`thread2`任务完成。

using System.Threading.Tasks;
    using System.Threading;
    
    class Program
    {
        static void Main(string[] args)
        {
            Task task1 = Task.Factory.StartNew(() => doStuff("Task1"));
            Task task2 = Task.Factory.StartNew(() => doStuff("Task2"));
            Task task3 = Task.Factory.StartNew(() => doStuff("Task3"));
            Task.WaitAll(task1, task2, task3);
    
            Console.WriteLine("All threads complete");
            Console.ReadLine();
        }
    
        static void doStuff(string strName)
        {
            for (int i = 1; i <= 3; i++)
            {
                Console.WriteLine(strName + " " + i.ToString());
                Thread.Yield();
            }
        }
    }

Task3 1
    Task1 1
    Task3 2
    Task1 2
    Task2 1
    Task1 3
    Task3 3
    Task2 2
    Task2 3
    All threads complete

### [Thread.Join()等待线程以C\#方法结束][Thread.Join_C] ###

上面的部分`Task.WaitAll()`描述了如何使用 C\# 方法来等待一个线程。您可以使用C\#`Thread.Join()`方法实现相同的目标。[Thread.Join()该方法][Thread.Join]停止调用线程的执行，直到当前线程完成执行。下面的代码示例展示了如何使用 C\#`Thread.Join()`方法等待线程完成执行。

using System;
    using System.Threading.Tasks;
    
    namespace wait_for_thread
    {
        class Program
        {
            static void fun1()
            {
                for(int i = 0; i < 2; i++)
                {
                    Console.WriteLine("Thread 1");
                }
            }
            static void fun2()
            {
                for (int i = 0; i < 2; i++)
                {
                    Console.WriteLine("Thread 2");
                }
            }
            static void Main(string[] args)
            {
                Thread thread1 = new Thread(new ThreadStart(fun1));
                Thread thread2 = new Thread(new ThreadStart(fun2));
                
                thread1.Start();
                thread1.Join();
                thread2.Start();
                thread2.Join();
                Console.WriteLine("The End");
            }
        }
    }

输出：

Thread 1
    Thread 1
    Thread 2
    Thread 2
    The End

在上面的代码中，我使用了一个 C\#`Thread.Join()`方法来等待`thread1`线程和`thread2`线程在主线程内完成。

using System.Threading.Tasks;
    using System.Threading;
    
    class Program
    {
        static void Main(string[] args)
        {
            Thread t1 = new Thread(doStuff);
            t1.Start("Task1");
            Thread t2 = new Thread(doStuff);
            t2.Start("Task2");
            Thread t3 = new Thread(doStuff);
            t3.Start("Task3");
            t1.Join(); //wait here until t1 has terminated...
            t2.Join(); //wait here until t2 has terminated...
            t3.Join(); //wait here until t3 has terminated...
            Console.WriteLine("All threads complete");
        }
        static void doStuff(object strName)
        {
            for (int i = 1; i <= 3; i++)
            {
                Console.WriteLine(strName + " " + i.ToString());
                Thread.Yield();
            }
        }
    }

Task1 1
    Task1 2
    Task1 3
    Task2 1
    Task2 2
    Task2 3
    Task3 1
    Task3 2
    Task3 3
    All threads complete

[Task.WaitAll_ C]: https://www.delftstack.com/ja/howto/csharp/wait-for-thread-to-finish-in-csharp/#c%23-%25E3%2581%25AE-task.waitall-%25E3%2583%25A1%25E3%2582%25BD%25E3%2583%2583%25E3%2583%2589%25E3%2581%25A7%25E3%2582%25B9%25E3%2583%25AC%25E3%2583%2583%25E3%2583%2589%25E3%2581%258C%25E7%25B5%2582%25E4%25BA%2586%25E3%2581%2599%25E3%2582%258B%25E3%2581%25AE%25E3%2582%2592%25E5%25BE%2585%25E3%2581%25A4
[Thread.Join_ C]: https://www.delftstack.com/ja/howto/csharp/wait-for-thread-to-finish-in-csharp/#c%23-%25E3%2581%25AE-thread.join-%25E3%2583%25A1%25E3%2582%25BD%25E3%2583%2583%25E3%2583%2589%25E3%2581%25A7%25E3%2582%25B9%25E3%2583%25AC%25E3%2583%2583%25E3%2583%2589%25E3%2581%258C%25E7%25B5%2582%25E4%25BA%2586%25E3%2581%2599%25E3%2582%258B%25E3%2581%25AE%25E3%2582%2592%25E5%25BE%2585%25E3%2581%25A4
[Task.WaitAll_C]: https://www.delftstack.com/ja/howto/csharp/wait-for-thread-to-finish-in-csharp/#c-%E3%81%AE-task-waitall-%E3%83%A1%E3%82%BD%E3%83%83%E3%83%89%E3%81%A7%E3%82%B9%E3%83%AC%E3%83%83%E3%83%89%E3%81%8C%E7%B5%82%E4%BA%86%E3%81%99%E3%82%8B%E3%81%AE%E3%82%92%E5%BE%85%E3%81%A4
[Task.WaitAll]: https://docs.microsoft.com/ja-jp/dotnet/api/system.threading.tasks.task.waitall?view=net-5.0
[Task]: https://docs.microsoft.com/ja-jp/dotnet/api/system.threading.tasks.task?view=net-5.0
[Thread.Join_C]: https://www.delftstack.com/ja/howto/csharp/wait-for-thread-to-finish-in-csharp/#c-%E3%81%AE-thread-join-%E3%83%A1%E3%82%BD%E3%83%83%E3%83%89%E3%81%A7%E3%82%B9%E3%83%AC%E3%83%83%E3%83%89%E3%81%8C%E7%B5%82%E4%BA%86%E3%81%99%E3%82%8B%E3%81%AE%E3%82%92%E5%BE%85%E3%81%A4
[Thread.Join]: https://docs.microsoft.com/ja-jp/dotnet/api/system.threading.thread.join?view=net-5.0