@JSONPropertyIgnore注解org.json序列化java对象时忽略部分属性

迈不过友情╰ 2023-09-30 10:14 13阅读 0赞

##  ##

import org.json.JSONPropertyIgnore;
    
    public class Person {
    
        private String name;
        private String about;
        private int birthYear;
        private String password;
    
        public Person(String name, String about, int birthYear, String password) {
            this.name = name;
            this.about = about;
            this.birthYear = birthYear;
            this.password = password;
        }
    
        public String getName() {
            return name;
        }
    
        public void setName(String name) {
            this.name = name;
        }
    
        public String getAbout() {
            return about;
        }
    
        public void setAbout(String about) {
            this.about = about;
        }
    
        public int getBirthYear() {
            return birthYear;
        }
    
        public void setBirthYear(int birthYear) {
            this.birthYear = birthYear;
        }
    
        @JSONPropertyIgnore
        public String getPassword() {
            return password;
        }
    
        public void setPassword(String password) {
            this.password = password;
        }
    
    }

Person person = DataStore.getInstance().getPerson(name);
    
            if (person != null) {
    //            String json = "{\n";
    //            json += "\"name\": " + JSONObject.quote(person.getName()) + ",\n";
    //            json += "\"about\": " + JSONObject.quote(person.getAbout()) + ",\n";
    //            json += "\"birthYear\": " + person.getBirthYear() + "\n";
    //            json += "}";
    //            response.getOutputStream().println(json);
                JSONObject object = new JSONObject(person);
                String jsonstring = object.toString();
                System.out.println(jsonstring);
                response.getOutputStream().println(jsonstring);
    
            } else {
                //That person wasn't found, so return an empty JSON object. We could also return an error.
                response.getOutputStream().println("{}");
            }

java对象完整属性输出：

\{"password":"one","birthYear":1816,"name":"Ada","about":"Ada Lovelace was the first programmer."\}

使用注解忽略password属性

@JSONPropertyIgnore  
public String getPassword() \{  
return password;  
\}

java对象忽略部分属性输出：

\{"birthYear":1815,"name":"Ada","about":"Ada Lovelace was the first programmer."\}