org.json.JSONException: Value Response of type java.lang.String cannot be converted to JSONObject

àì夳堔傛蜴生んèń 2023-09-26 09:30 71阅读 0赞

## 问题 ##

android通过okhttp调用后端接口，对于json返回数据解析, android studio控制台报错

### 详细问题 ###

2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err: org.json.JSONException: Value Response of type java.lang.String cannot be converted to JSONObject
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at org.json.JSON.typeMismatch(JSON.java:112)
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at org.json.JSONObject.<init>(JSONObject.java:168)
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at org.json.JSONObject.<init>(JSONObject.java:181)
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at com.example.electronicmall.test.User.UserNewInfoActivity$1$1.onResponse(UserNewInfoActivity.java:103)
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at com.squareup.okhttp.Call$AsyncCall.execute(Call.java:168)
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at com.squareup.okhttp.internal.NamedRunnable.run(NamedRunnable.java:33)
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1167)
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:641)
    2022-09-25 17:31:52.304 28574-28733/com.example.electronicmall W/System.err:     at java.lang.Thread.run(Thread.java:929)
    2022-09-25 17:32:27.455 28574-28596/com.example.electronicmall W/System: A resource failed to call close.

### 解决方案 ###

对于json数据解析时，删除源字符串中的隐藏字符  
即  
JSONObject(json.substring(json.indexOf(“\{”), json.lastIndexOf(“\}”) + 1));  
对于笔者而言  
将

String responseData = response.body().string();
    JSONObject jsonObject = new JSONObject(responseData);

改为

String responseData = responseData1.substring(responseData1.indexOf("{"), responseData1.lastIndexOf("}") + 1);
    JSONObject jsonObject = new JSONObject(responseData);

即可

### 原因 ###

由于在编写String时添加了不需要的字符。使用return new JSONObject（json.substring（json.indexOf（“\{”），json.lastIndexOf“\}”）+1）；删除源字符串中的隐藏字符。

### 参考文献 ###

[JSONException: Value of type java.lang.String cannot be converted to JSONObject][JSONException_ Value of type java.lang.String cannot be converted to JSONObject]

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[JSONException_ Value of type java.lang.String cannot be converted to JSONObject]: https://stackoverflow.com/questions/10267910
[9cb4cb80a18345158f8a69e2f196e5b9.png]: https://img-blog.csdnimg.cn/9cb4cb80a18345158f8a69e2f196e5b9.png