opencv的yolo报错：IndexError: invalid index to scalar variable

ゞ浴缸里的玫瑰 2023-09-24 19:54 36阅读 0赞

## opencv的yolo报错：IndexError: invalid index to scalar variable，Python ##

几年前写的老代码工程：

[https://zhangphil.blog.csdn.net/article/details/102960822![icon-default.png_t_N176][]https://zhangphil.blog.csdn.net/article/details/102960822][https_zhangphil.blog.csdn.net_article_details_102960822_icon-default.png_t_N176_https_zhangphil.blog.csdn.net_article_details_102960822]

重新运行后报错：

> Traceback (most recent call last):  
> File "D:\\code\\python\\yolo\\main.py", line 45, in <module>  
> outputs = net.forward(get\_output\_layers(net))  
> ^^^^^^^^^^^^^^^^^^^^^^  
> File "D:\\code\\python\\yolo\\main.py", line 9, in get\_output\_layers  
> output\_layers = \[layer\_names\[arr\[0\] - 1\] for arr in net.getUnconnectedOutLayers()\]  
> ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^  
> File "D:\\code\\python\\yolo\\main.py", line 9, in <listcomp>  
> output\_layers = \[layer\_names\[arr\[0\] - 1\] for arr in net.getUnconnectedOutLayers()\]  
> ~~~^^^  
> IndexError: invalid index to scalar variable.

原因是opencv版本升级。解决方案，把第9行代码：

output_layers = [layer_names[arr[0] - 1] for arr in net.getUnconnectedOutLayers()]

修改成：

output_layers = [layer_names[i - 1] for i in net.getUnconnectedOutLayers()]

然后重新运行成功。

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[https_zhangphil.blog.csdn.net_article_details_102960822_icon-default.png_t_N176_https_zhangphil.blog.csdn.net_article_details_102960822]: https://zhangphil.blog.csdn.net/article/details/102960822