【已解决】TypeError: checkboxState() takes 1 positional argument but 2 were given

骑猪看日落 2023-07-06 10:28 14阅读 0赞

今天在学习pyqt复选框的时候，在运行校demo时出现错误：

TypeError: checkboxState() takes 1 positional argument but 2 were given

而我的相关代码是这样的：

''' 复选框 三种状态 未选中：0 半选中：1 选中：2 '''
    import sys
    from PyQt5.QtCore import *
    from PyQt5.QtGui import  *
    from PyQt5.QtWidgets import *
    from PyQt5.QtCore import Qt
    
    class QCheckBoxDemo(QWidget):
        def __init__(self):
            super(QCheckBoxDemo,self).__init__()
            self.initUI()
    
        def initUI(self):
            self.setWindowTitle('复选框')
    
            layout=QHBoxLayout()
    
            self.checkBox1=QCheckBox('1')
            self.checkBox1.setChecked(True)
            self.checkBox1.stateChanged.connect(lambda:self.checkboxState(self.checkBox1))
            layout.addWidget(self.checkBox1)
    
            self.checkBox2 = QCheckBox('2')
            self.checkBox2.stateChanged.connect(lambda: self.checkboxState(self.checkBox2))
            layout.addWidget(self.checkBox2)
    
            self.checkBox3 = QCheckBox('半选中')
            #提示错误在下面这行
            self.checkBox3.stateChanged.connect(lambda: self.checkboxState(self.checkBox3)) 
            self.checkBox3.setTristate(True)
            self.checkBox3.setCheckState(Qt.PartiallyChecked)
            layout.addWidget(self.checkBox3)
            self.setLayout(layout)
    
        def checkboxState(self): #########有错
            check1Status = self.checkBox1.text()+', isChecked='+str(self.checkBox1.isChecked()) +'checkState='+str(self.checkBox1.checkState())+'\n'
            check2Status = self.checkBox2.text() + ', isChecked=' + str(self.checkBox2.isChecked()) + 'checkState=' + str(self.checkBox2.checkState()) + '\n'
            check3Status = self.checkBox3.text() + ', isChecked=' + str(self.checkBox3.isChecked()) + 'checkState=' + str(self.checkBox3.checkState()) + '\n'
            print(check1Status+check2Status+check3Status)
    
    if __name__=='__main__':
        app=QApplication(sys.argv)
        main=QCheckBoxDemo()
        main.show()
        sys.exit(app.exec_())

提示错误指向的是这里：  
![在这里插入图片描述][20200217233851757.png]但是我咋也没看出这里有错，而我查阅资料才知道：在类调用类内部函数时，会自动传入self参数；举个例子如果函数中不写self，那么参数只有x，但是在函数调用是传入参数是（self，x）两个参数，所以函数就会报错。  
所以实际上应该把这里：  
![在这里插入图片描述][20200217233950895.png]  
改成这样，就可以解决：

def checkboxState(self,cb):
    	......

参考：

*  [TypeError: xxx takes 1 positional argument but 2 were given解决方法][TypeError_ xxx takes 1 positional argument but 2 were given]

[20200217233851757.png]: https://img-blog.csdnimg.cn/20200217233851757.png
[20200217233950895.png]: https://img-blog.csdnimg.cn/20200217233950895.png
[TypeError_ xxx takes 1 positional argument but 2 were given]: https://blog.csdn.net/suhao0911/article/details/91045818?ops_request_misc=%7B%22request_id%22:%22158195328719724847014668%22,%22scm%22:%2220140713.130056874..%22%7D&request_id=158195328719724847014668&biz_id=0&utm_source=distribute.pc_search_result.none-task