LInux 创建多个线程实现对一个数的增加

我就是我 2023-06-24 11:27 18阅读 0赞

## （一）运行结果 ##

![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3NoYXh1MTIz_size_16_color_FFFFFF_t_70]

## （二）代码 ##

#include<stdio.h>
    #include<unistd.h>
    #include<stdlib.h>
    #include<pthread.h>
    #define COUNT 15
    static  int   i = 0;
    pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;
    pthread_cond_t  even  = PTHREAD_COND_INITIALIZER;
    pthread_cond_t  uneven = PTHREAD_COND_INITIALIZER;
    void* thread_one(void *arg)
    { 
        while(i <= COUNT){ 
            pthread_mutex_lock(&mutex);
            if(i % 2 != 0){ 
                printf("pthread 1 : %d\n",i);
                ++i;
                pthread_cond_signal(&uneven);
            }
            else { 
                pthread_cond_wait(&even, &mutex);
            }
    	pthread_mutex_unlock(&mutex);
        }
    }
    void* thread_two(void *arg)
    { 
        while(i <= COUNT){ 
            pthread_mutex_lock(&mutex);
            if(i % 2 == 0){ 
                printf("pthread 2 : %d\n",i);
                ++i;
                pthread_cond_signal(&even);
            }
            else{ 
                pthread_cond_wait(&uneven, &mutex);
            }
    	pthread_mutex_unlock(&mutex);
        }
    }
    int main(){ 
        pthread_t tid1, tid2;
        pthread_create(&tid1, NULL, thread_one, NULL);
        pthread_create(&tid2, NULL, thread_two, NULL);
        pthread_join(tid1, NULL);
        pthread_join(tid2, NULL);
        return 0;
    }

## (三)编译及运行 ##

**编译**

gcc file.c -o file.out -lpthread

注意这个的文件的文件名名字是file.c, 同事也可以用下面的编译方法

gcc file.c -lpthread

用这种方法编译，默认的可执行文件的名字是a.out

**运行**

第一种编译的运行

./file.out

第二种编译的运行

./a.out

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