JSON格式转换为Java对象

素颜马尾好姑娘i 2023-06-10 05:21 20阅读 0赞

## （一）转换为Java对象 ##

代码

@Test
        public void test04() throws IOException { 
            String json ="{\"gender\":\"男\",\"age\":23,\"username\":\"ALworm\"}";
            ObjectMapper mapper = new ObjectMapper();
            Person person = mapper.readValue(json, Person.class);
            System.out.println(person);
        }

Person类

import com.fasterxml.jackson.annotation.JsonFormat;
    import com.fasterxml.jackson.annotation.JsonIgnore;
    
    import java.util.Date;
    
    public class Person { 
        private String username;
        private Integer age;
        private String gender;
    
        @JsonFormat(pattern = "yyyy-MM-dd")
        // @JsonIgnore //排除,忽略
        private Date birthday;
    
        @Override
        public String toString() { 
            return "Person{" +
                    "username='" + username + '\'' +
                    ", age=" + age +
                    ", gender='" + gender + '\'' +
                    ", birthday=" + birthday +
                    '}';
        }
    
        public String getUsername() { 
            return username;
        }
    
        public void setUsername(String username) { 
            this.username = username;
        }
    
        public Integer getAge() { 
            return age;
        }
    
        public void setAge(Integer age) { 
            this.age = age;
        }
    
        public String getGender() { 
            return gender;
        }
    
        public void setGender(String gender) { 
            this.gender = gender;
        }
    
        public Date getBirthday() { 
            return birthday;
        }
    
        public void setBirthday(Date birthday) { 
            this.birthday = birthday;
        }
    }