P4147-玉蟾宫

拼搏现实的明天。 2023-06-01 08:52 91阅读 0赞

1 #include <bits/stdc++.h>
     2 #define _for(i,a,b) for(int i = (a);i < b;i ++)
     3 #define _rep(i,a,b) for(int i = (a);i > b;i --)
     4 #define INF 0x3f3f3f3f
     5 #define MOD 1000000007
     6 typedef long long ll;
     7 using namespace std;
     8 inline ll read()
     9 {
    10     ll ans = 0;
    11     char ch = getchar(), last = ' ';
    12     while(!isdigit(ch)) last = ch, ch = getchar();
    13     while(isdigit(ch)) ans = (ans << 1) + (ans << 3) + ch - '0', ch = getchar();
    14     if(last == '-') ans = -ans;
    15     return ans;
    16 }
    17 inline void write(ll x)
    18 {
    19     if(x < 0) x = -x, putchar('-');
    20     if(x >= 10) write(x / 10);
    21     putchar(x % 10 + '0');
    22 }
    23 
    24 int N,M;
    25 int a[1003][1003]; 
    26 int lef[1003][1003];
    27 int ri[1003][1003];
    28 int up[1003][1003];
    29 int main()
    30 {
    31     N = read(),M = read();
    32     _for(i,1,N+1)
    33         _for(j,1,M+1)
    34         {
    35             char c;
    36             cin >> c;
    37             if(c=='R')
    38                 a[i][j] = 1;
    39             else
    40                 a[i][j] = 0;
    41         }
    42             
    43     _for(j,1,M+1)
    44     {
    45         if(!a[1][j])
    46             up[1][j] = 1;
    47         _for(i,2,N+1)
    48             if(!a[i][j])
    49                 up[i][j] = up[i-1][j]+1;
    50     }
    51     
    52     _for(i,1,N+1)
    53     {
    54         if(!a[i][1])
    55             lef[i][1] = 1;
    56         _for(j,2,M+1)
    57             if(!a[i][j])
    58                 lef[i][j] = lef[i][j-1]+1;
    59     }
    60     
    61     _for(i,1,N+1)
    62     {
    63         if(!a[i][M])
    64             ri[i][M] = 1;
    65         _rep(j,M-1,0)
    66             if(!a[i][j])
    67                 ri[i][j] = ri[i][j+1]+1;
    68     }
    69     int ans = 0;
    70     _for(i,1,N+1)
    71          _for(j,1,M+1)
    72          {
    73              if(i>1 && !a[i][j] && !a[i-1][j])
    74              {
    75                 lef[i][j] = min(lef[i-1][j],lef[i][j]);
    76                  ri[i][j] = min(ri[i-1][j],ri[i][j]);
    77              }
    78             ans = max(ans,up[i][j]*(ri[i][j]+lef[i][j]-1));
    79         }
    80     write(3*ans);
    81     return 0;
    82 }

转载于:https://www.cnblogs.com/Asurudo/p/11424924.html