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根据操作写递归就行了，注意一点，data不是从1到n顺序来的，所以要自己去获取push后面的数字，不能简单的用计数器++。 include <iostream>
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众所周知只有前序遍历和后序遍历是不可能推出中序遍历的，所以我就不废话了 由树的前序遍历和中序遍历可以推后序遍历 由树的中序遍历和后序遍历可以推前序遍历 incl
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题意： 给出两个集合，从这两个集合里面选出数量相同的元素进行一对一相乘，求能够得到的最大乘积之和。 题解： 对每个集合，将正数和负数分开考虑，将每个集合里的整数从大到小排
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