【python】获取目录下的最新文件夹/文件

r囧r小猫 2023-01-03 04:53 217阅读 0赞

def new_report(test_report):
        lists = os.listdir(test_report)                                    #列出目录的下所有文件和文件夹保存到lists
        print(list)
        lists.sort(key=lambda fn:os.path.getmtime(test_report + "\\" + fn))#按时间排序
        file_new = os.path.join(test_report,lists[-1])                     #获取最新的文件保存到file_new
        print(file_new)
        return file_new
    if __name__=="__main__":
        test_report="path"#目录地址
        new_report(test_report)

df_data=dataPress(fileName)
    # os.remove(u'./upload/{}'.format(fileName))
    
    
    def get_filelist(dir, Filelist):
        try:
            lists = os.listdir(dir) 
            lists.sort(key=lambda fn:os.path.getmtime(dir + "\\" + fn))
            if len(lists)>1:
                lists=[i for i in lists if (R"xlsx" in i)]
                for i in lists:
                    print(i)
                    if i !=lists[-1] or R"xlsx" not in i :
                        os.remove(u'./upload/{}'.format(i))
            file_new = lists[-1]       
            print(file_new)
            if R"xlsx" in file_new:
                return file_new
            # for s in os.listdir(dir):
            #     if R"xlsx" in s:
            #         print(s)
            #         Filelist.append(s) 
            # return Filelist[0]
        except Exception,err:
            print(err)
            return Filelist
    
    def dataPress(fileName):
        print("done >>>>>>>>>>",fileName.decode("utf-8"))
        try:
            excel_reader=pd.ExcelFile(u'./upload/{}'.format(fileName))
        except Exception,err:
            if R"xlsx" in str(err):
                df=pd.ExcelFile(u'./upload/{}'.format(fileName),engine='openpyxl')
        sheet_names = excel_reader.sheet_names
        lis=[]
        if R"dataflow" in sheet_names:
            df_data =  excel_reader.parse(sheet_name="dataflow")
            df_=df_data.iloc[1:5,1:5]
            df_.iloc[:,2:4] = np.nan
            for tup in df_.itertuples():
                lis.append(tup[1:])
                # print(tup[1:])
        print(lis)
        return lis
        # result = _common.mysql_select(sql, withcolumns=False)