go极简代码将byte数组转为二进制字符串，不足8位自动填充

傷城~ 2022-12-29 14:27 114阅读 0赞

需要以二进制的形式查看byte数组，怎么写呢？直接上代码。

func BytesToBinaryString(bs []byte) string { 
    	buf := bytes.NewBuffer([]byte{ })
    	for _, v := range bs { 
    		buf.WriteString(fmt.Sprintf("%08b", v))
    	}
    	return buf.String()
    }

附上测试用例

func TestBytesToBinaryString(t *testing.T) { 
    	type testcase struct { 
    		bytes     []byte
    		expectRes string
    	}
    
    	testcases := []testcase{ }
    
    	testcases = append(testcases, testcase{ 
    		bytes:     []byte{ 1},
    		expectRes: "00000001",
    	})
    
    	testcases = append(testcases, testcase{ 
    		bytes:     []byte{ 0, 1},
    		expectRes: "0000000000000001",
    	})
    
    	testcases = append(testcases, testcase{ 
    		bytes:     []byte{ 255, 254},
    		expectRes: "1111111111111110",
    	})
    
    	testcases = append(testcases, testcase{ 
    		bytes:     []byte{ 0, 2, 0},
    		expectRes: "000000000000001000000000",
    	})
    
    	for _, v := range testcases { 
    		res := BytesToBinaryString(v.bytes)
    		t.Logf("testcase [%+v] expect [%s], get [%s]", v.bytes, v.expectRes, res)
    		if res != v.expectRes { 
    			t.Error("fail")
    		}
    	}
    }

测试结果：

=== RUN   TestBytesToBinaryString
    --- PASS: TestBytesToBinaryString (0.00s)
        numberUtil_test.go:145: testcase [[1]] expect [00000001], get [00000001]
        numberUtil_test.go:145: testcase [[0 1]] expect [0000000000000001], get [0000000000000001]
        numberUtil_test.go:145: testcase [[255 254]] expect [1111111111111110], get [1111111111111110]
        numberUtil_test.go:145: testcase [[0 2 0]] expect [000000000000001000000000], get [000000000000001000000000]
    PASS