[golang]-根据json中的某个key的值输出对应的id

约定不等于承诺〃 2022-12-27 12:43 185阅读 0赞

导语：有一段json 如下 ，想根据传入的username的值匹配到对应的id。 对应功能是传入username，找到对应的id，删除对应的用户。

思路是 循环遍历这个数组，然后判断 看看username是否等于输入的username，如果等于输出对应索引的id。

直接上代码

package api
    
    import (
    	"encoding/json"
    	"fmt"
    
    	"github.com/astaxie/beego"
    )
    
    
    type TestController struct { 
    	BaseController
    }
    
    type Person struct { 
    	Id int
    	// Name string
    	Username string
    }
    func (c *TestController) Get() { 
    	var jsonBlob = []byte(`[ {"id":12,"name":"阿斯顿2","username":"asidun2"}, {"id":11,"name":"阿斯顿","username":"asidun"}, {"id":10,"name":"阿狗","username":"agou"}, {"id":9,"name":"阿猫","username":"amao"}, {"id":8,"name":"GitLab Alert Bot","username":"alert-bot"}, {"id":1,"name":"Administrator","username":"root"} ]`)
    	var person []Person
    
    	err := json.Unmarshal(jsonBlob, &person)
    	if err != nil { 
    		fmt.Println("error:", err)
    	}
    	beego.Info("jq")
    	fmt.Printf("%+v", person)
    
    	fmt.Printf("out type:%T\n", person)
    	beego.Info("jq")
    	// beego.Info("jq")
    	// beego.Info(jq)
    	for _, v := range person { 
    		// beego.Info(v)
    		beego.Info(v.Id, v.Username)
    		if v.Username != "asidun" { 
    			beego.Info("用户名不匹配", v.Username)
    		} else { 
    			beego.Info("用户名匹配成功", v.Username)
    		}
    
    		fmt.Printf("out type:%T\n", v)
    	}
    	c.Ctx.WriteString("content string")
    
    }

直接请求http://localhost:8080/api/test

![710ec7d72584d1244bbfbaecde3fd2ff.png][]

参考

https://blog.csdn.net/hp\_cpp/article/details/101058472

[710ec7d72584d1244bbfbaecde3fd2ff.png]: /images/20221120/ef7fdfa164774dc29263edfffbfa6b9c.png