Python+OpenCV：Hough圆检测(Hough Circle Transform)

深碍√TFBOYSˉ_ 2022-12-21 15:49 198阅读 0赞

## Python+OpenCV：Hough圆检测(Hough Circle Transform) ##

####################################################################################################
    # Hough圆检测(Hough Circle Transform)
    def lmc_cv_image_hough_circle_transform():
        """
            函数功能: Hough圆检测(Hough Circle Transform)。
        """
    
        # 读取图像
        image = lmc_cv.imread('D:/99-Research/Python/Image/opencv-logo-white.png', flags=lmc_cv.IMREAD_UNCHANGED)
        rgb_image = lmc_cv.cvtColor(image, lmc_cv.COLOR_BGR2RGB)
        gray_image = lmc_cv.cvtColor(rgb_image, lmc_cv.COLOR_RGB2GRAY)
        pyplot.figure('Image Display')
        pyplot.subplot(1, 2, 1)
        pyplot.imshow(rgb_image, cmap='gray')
        pyplot.title('Original Image')
        pyplot.xticks([])
        pyplot.yticks([])
    
        # Hough圆检测(Hough Circle Transform)
        gray_image = lmc_cv.medianBlur(gray_image, 3)
        cimg = lmc_cv.cvtColor(gray_image, lmc_cv.COLOR_GRAY2BGR)
        circles = lmc_cv.HoughCircles(gray_image, method=lmc_cv.HOUGH_GRADIENT, dp=1, minDist=100,
                                      param1=80, param2=30, minRadius=50, maxRadius=0)
        circles = np.uint16(np.around(circles))
        for i in circles[0, :]:
            # draw the outer circle
            lmc_cv.circle(cimg, (i[0], i[1]), i[2], (0, 255, 0), 2)
            # draw the center of the circle
            lmc_cv.circle(cimg, (i[0], i[1]), 2, (255, 0, 0), 3)
        pyplot.subplot(1, 2, 2)
        pyplot.imshow(cimg, cmap='gray')
        pyplot.title('Hough Circle Transform Image')
        pyplot.xticks([])
        pyplot.yticks([])
    
        # 根据用户输入保存图像
        if ord("q") == (lmc_cv.waitKey(0) & 0xFF):
            # 销毁窗口
            pyplot.close('all')
        return

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