C/C++编程：删除string中的所有能够找到的某个子串

深碍√TFBOYSˉ_ 2022-12-20 03:10 118阅读 0赞

#include <iostream>
    #include <map>
    #include <string>
    using namespace std;
    
    void deleteAllMark(string &s, const string &mark)
    {
        
        size_t nSize = mark.size();
        while(true)
        {
        
            size_t pos = s.find(mark);    //  尤其是这里
            if(pos == string::npos)
            {
        
                return;
            }
    
            s.erase(pos, nSize);
        }
    }
    
    int main()
    {
        
        string s = "\"02178592720826820101#bd121affb8a842dd8dcd41457ca1575b\"";
        cout << s << "\n";
        deleteAllMark(s, "\"");
        cout << s << "\n";
    
        return 0;
    }

#include   <string>     
        #include   <iostream>     
        using   namespace   std;     
        string&   replace_all(string&   str,const   string&   old_value,const   string&   new_value)     
        {
             
            while(true)   {
             
                string::size_type   pos(0);     
                if(   (pos=str.find(old_value))!=string::npos   )     
                    str.replace(pos,old_value.length(),new_value);     
                else   break;     
            }     
            return   str;     
        }     
        string&   replace_all_distinct(string&   str,const   string&   old_value,const   string&   new_value)     
        {
             
            for(string::size_type   pos(0);   pos!=string::npos;   pos+=new_value.length())   {
             
                if(   (pos=str.find(old_value,pos))!=string::npos   )     
                    str.replace(pos,old_value.length(),new_value);     
                else   break;     
            }     
            return   str;     
        }     
        int   main()     
        {
             
            cout   <<   replace_all(string("12212"),"12","21")   <<   endl;     
            cout   <<   replace_all_distinct(string("12212"),"12","21")   <<   endl;     
        }     
        /* 
        输出如下:    
        22211    
        21221 
        */