显示屏

Dear 丶 2022-12-04 07:59 175阅读 0赞

液晶屏上，每个阿拉伯数字都是可以显示成 3×5 的点阵的（其中 X 表示亮点，. 表示暗点）。现在给出数字位数（不超过 100）和一串数字，要求输出这些数字在显示屏上的效果。数字的显示方式如同样例输出，注意每个数字之间都有一列间隔。

###### 输入 ######

10
    0123456789

###### 输出 ######

XXX...X.XXX.XXX.X.X.XXX.XXX.XXX.XXX.XXX
    X.X...X...X...X.X.X.X...X.....X.X.X.X.X
    X.X...X.XXX.XXX.XXX.XXX.XXX...X.XXX.XXX
    X.X...X.X.....X...X...X.X.X...X.X.X...X
    XXX...X.XXX.XXX...X.XXX.XXX...X.XXX.XXX

//模块化 
    #include<bits/stdc++.h>
    using namespace std;
    int n; 
    string s[5];
    char c;
    map<char,char> anti;
    inline void addline(const int &l,const int &r,const char &p){ for(int i=l;i<=r;i++) s[i]+=p;return;}//addline(l,r,p)表示把第l到r行每行末尾增加字符p
    inline void dp(){ s[0]+='X',s[1]+='.',s[2]+='X',s[3]+='.',s[4]+='X';return;}//作用：增加一列 
    inline void st(const int &l,const char &p){ for(int i=0;i<5;i++) s[i]+=((i==l)?p:anti[p]);return;}//st(l,p)表示只在第l行末尾增加字符p，其他行末尾每行增加不同于p的另外一种字符
    int main()
    { 
        scanf("%d",&n);
        getchar();getchar(); 
        anti['X']='.';anti['.']='X';
        for(int i=1;i<=n;i++)
        { 
      	scanf("%c",&c); 
      	if(i!=1) addline(0,4,'.'); //间隔
      	if(c=='0') addline(0,4,'X'),s[0]+='X',addline(1,3,'.'),s[4]+='X',addline(0,4,'X');
      	if(c=='1') addline(0,4,'.'),addline(0,4,'.'),addline(0,4,'X');
      	if(c=='2') s[0]+='X',s[1]+='.',addline(2,4,'X'),dp(),addline(0,2,'X'),s[3]+='.',s[4]+='X';
      	if(c=='3') dp(),dp(),addline(0,4,'X');
      	if(c=='4') addline(0,2,'X'),addline(3,4,'.'),st(2,'X'),addline(0,4,'X');
      	if(c=='5') st(3,'.'),dp(),st(1,'.');
      	if(c=='6') addline(0,4,'X'),dp(),st(1,'.');
      	if(c=='7') st(0,'X'),st(0,'X'),addline(0,4,'X');
      	if(c=='8') addline(0,4,'X'),dp(),addline(0,4,'X');
      	if(c=='9') st(3,'.'),dp(),addline(0,4,'X');
        }
        for(int i=0;i<5;i++) cout<<s[i]<<endl; 
        return 0;
    }

或

//普通二维数组定义
    #include <iostream>
    #include <cstdio>
    #include <string>
    using namespace std;
    string s[10][5]=
    { 
    { "XXX","X.X","X.X","X.X","XXX"},//0
    { "..X","..X","..X","..X","..X"},//1
    { "XXX","..X","XXX","X..","XXX"},//2
    { "XXX","..X","XXX","..X","XXX"},//3
    { "X.X","X.X","XXX","..X","..X"},//4
    { "XXX","X..","XXX","..X","XXX"},//5
    { "XXX","X..","XXX","X.X","XXX"},//6
    { "XXX","..X","..X","..X","..X"},//7
    { "XXX","X.X","XXX","X.X","XXX"},//8
    { "XXX","X.X","XXX","..X","XXX"},//9
    };
    int main()
    { 
        int n;
        string in;
        cin>>n;
        cin>>in;
        for(int i=0;i<5;i++)
        { 
      	for(int j=0;j<n;j++)
      	{ 
                cout<<s[in[j]-'0'][i];
                if(j!=n-1)
        		cout<<'.';
      	} 
      	cout<<endl;
        }
        return 0;
    }