大数字符串反转

╰+攻爆jí腚メ 2022-10-25 14:12 5阅读 0赞

/* * @lc app=leetcode.cn id=7 lang=javascript * * [7] 整数反转 */
    
    
    /** * 给你一个32位的有符号数字字符串x，返回x中每位上的数字反转后的结果 * 如果反转后整数超过32位的有符号整数的范围[-2^21, 2^31 - 1]，就返回0 * 示例： * 1、输入：232423424242342424324.43 * 输出：34.423424243242424324232 * 2、输入：2342134.23423424 * 输出：42432432.4312432 * 3、输入：12.121423423425432534534 * 输出：435435234524324324121.21 * 4、输入：-0.3000000000000000 * 输出：-3.0 * 5、输入：-0.0000000000000000000000234234 * 输出：-4324320000000000000000000000.0 */
    
    // @lc code=start
    /** * @param {string} x * @return {string} */
    var reverse = function(x) { 
        let newX = x,
            xStr = x.toString(),
            len = xStr.length,
            MAX_VALUE = 2 ** 31
        console.log(`xStr.indexOf('.') : `, xStr)
        if (xStr.indexOf('.') !== -1) { 
            newX = xStr.substring(xStr.indexOf('.') + 1, len)
                    .split('')
                    .reverse()
                    .join('')
        } 
        console.log(`newX : `, newX)
        if (x < -MAX_VALUE && x > MAX_VALUE && newX < -MAX_VALUE && newX > MAX_VALUE) { 
            return 0
        } else { 
            let isSymbol = xStr.charAt(0) === '-'
            return (isSymbol ? '-' : '') + 
                    xStr.substring(1, len)
                        .split('')
                        .reverse()
                        .join('')
                        .replace(/^[0\1]+/g, '') + 
                    (isSymbol ? '' : xStr.charAt(0))
        }
    
    };
    // @lc code=end
    
    const result1 = reverse('232423424242342424324.43')
    console.log(`result1 : `, result1)
    const result2 = reverse('2342134.23423424')
    console.log(`result2 : `, result2)
    const result3 = reverse('12.121423423425432534534')
    console.log(`result3 : `, result3)
    const result4 = reverse('-0.3000000000000000')
    console.log(`result4 : `, result4)
    const result5 = reverse('-0.0000000000000000000000234234')
    console.log(`result5 : `, result5)