android把布局旋转,Android布局视图围绕圆圈旋转和间隔？

深碍√TFBOYSˉ_ 2022-10-18 10:00 145阅读 0赞

这是一个这样做的例子。 我创建了一个新的Android项目，并用FrameLayout替换了已经存在的RelativeLayout 。 它只是> = API 11，因为在View中转换和旋转调用：

我将在代码中创建一些快速视图，只需用您拥有的任何视图替换它们。 我将它们全部放在布局的中心，将LayoutParams的重力设置为Gravity.CENTER 。 然后，我正在翻译并将它们旋转到正确的位置：

@Override protected void onCreate(Bundle savedInstanceState) \{ super.onCreate(savedInstanceState); setContentView(R.layout.activity\_main); final FrameLayout main = (FrameLayout)findViewById(R.id.main); int numViews = 8; for(int i = 0; i < numViews; i++) \{ // Create some quick TextViews that can be placed. TextView v = new TextView(this); // Set a text and center it in each view. v.setText("View " + i); v.setGravity(Gravity.CENTER); v.setBackgroundColor(0xffff0000); // Force the views to a nice size (150x100 px) that fits my display. // This should of course be done in a display size independent way. FrameLayout.LayoutParams lp = new FrameLayout.LayoutParams(150, 100); // Place all views in the center of the layout. We'll transform them // away from there in the code below. lp.gravity = Gravity.CENTER; // Set layout params on view. v.setLayoutParams(lp); // Calculate the angle of the current view. Adjust by 90 degrees to // get View 0 at the top. We need the angle in degrees and radians. float angleDeg = i \* 360.0f / numViews - 90.0f; float angleRad = (float)(angleDeg \* Math.PI / 180.0f); // Calculate the position of the view, offset from center (300 px from // center). Again, this should be done in a display size independent way. v.setTranslationX(300 \* (float)Math.cos(angleRad)); v.setTranslationY(300 \* (float)Math.sin(angleRad)); // Set the rotation of the view. v.setRotation(angleDeg + 90.0f); main.addView(v); \} \}

这就是结果：

![IaHoK.png][]

[IaHoK.png]: http://img.androidcookie.com/android/IaHoK.png