C#设置和获取byte中某一bit的值

落日映苍穹つ 2022-10-07 05:56 549阅读 0赞

using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text;
    
    namespace Util
    {
        public class BitToByteUtil
        {
            /// <summary>
            /// 设置某一位的值
            /// </summary>
            /// <param name="data">需要设置的byte数据</param>
            /// <param name="index">要设置的位， 值从低到高为 1-8</param>
            /// <param name="flag">要设置的值 true / false</param>
            /// <returns></returns>
            public static byte set_bit(byte data, int index, bool flag)
            {
                if (index > 8 || index < 1)
                    throw new ArgumentOutOfRangeException();
                int v = index < 2 ? index : (2 << (index - 2));
                return flag ? (byte)(data | v) : (byte)(data & ~v);
            }
    
            /// <summary>
            /// 获取某一位的值
            /// 获取一个字节中的每一位的值，需要分别与128 64 32 16 8 4 2 1相与&运算
            /// 假设字节为byte1
            /// bit8 = byte1 & 128 == 128 ? 1 : 0;
            /// bit7 = byte1 & 64 == 64 ? 1 : 0;
            /// bit6 = byte1 & 32 == 32 ? 1 : 0;
            /// bit5 = byte1 & 16 == 16 ? 1 : 0;
            /// bit4 = byte1 & 8 == 8 ? 1 : 0;
            /// bit3 = byte1 & 4 == 4 ? 1 : 0;
            /// bit2 = byte1 & 2 == 2 ? 1 : 0;
            /// bit1 = byte1 & 1 == 1 ? 1 : 0;
            /// </summary>
            /// <param name="data">需要设置的byte数据</param>
            /// <param name="index">要取的位， 值从低到高为 1-8</param>
            /// <returns></returns>
            public static int get_bit(byte data, int index) {
                int bit = data & (Math.Pow(2, index - 1) == Math.Pow(2, index - 1) ? 1 : 0);
                return bit;
            }
        }
    }