刚发现C语言中数组还可以这么初始化

青旅半醒 2022-09-18 07:56 163阅读 0赞

在水木的CProgramming版看到的：

![None.gif][] char  str1\[ 32 \];  
![ExpandedBlockStart.gif][]![ContractedBlock.gif][] char  str2\[ 32 \] = ... \{ 0\} ;  
![ExpandedBlockStart.gif][]![ContractedBlock.gif][] char  str2\[ 32 \] = ... \{ 1\} ;  
![None.gif][]

在上述三种数组初始化方式中：  
  
数组str1中的32个元素的值为未指定的随机值；  
数组str2中，32个元素的值均为0 ;  
数组str3中，str3\[0\]的值为1，其余31个元素的值为0；  
  
以下是引用NetMD网友的解释：  
  
“按照标准，聚合类型(数组、结构等)的初始化被定义如下：  
  
被指定初始化值的部分由初始化值初始化；  
未被指定初始化值的部分由T()方式初始化；  
”  
  
下面是测试程序和结果

![None.gif][] \# include <stdio.h>   
![None.gif][]\# include <stdlib.h>   
![None.gif][]\# include <string.h>   
![None.gif][]   
![None.gif][]int main (a  , b)  
![None.gif][]  
![None.gif][]\{  
 ![None.gif][]  
![None.gif][] char str1\[ 32 \] = \{  1 \};  
![None.gif][] char str2\[ 32 \] = \{  0 \};  
![None.gif][]  
![None.gif][] int i;  
![None.gif][] for (i = 0 ; i < 32 ;i \++ )  
![None.gif][] printf ( " %d\_\_ " , str1\[i\]);  
![None.gif][] printf ( "  " );  
![None.gif][]  
![None.gif][] for (i = 0 ; i < 32 ;i \++ )  
![None.gif][] printf ( " %d\_\_ " , str2\[i\]);  
![None.gif][] printf ( "  " );  
![None.gif][]  
![None.gif][]\}  
![None.gif][]

![None.gif][] jekyll@ubuntu: ~/ prgramming$ . / a. out   
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![None.gif][]0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_  
![None.gif][]

[None.gif]: /images/20220828/d5b86dde69634db18a7716edb07a62b6.png
[ExpandedBlockStart.gif]: http://images.csdn.net/syntaxhighlighting/OutliningIndicators/ExpandedBlockStart.gif
[ContractedBlock.gif]: /images/20220828/3783c66a7e9d445eb909ddacc885553a.png