python中将字典相同key处理不同的value，将value相加给相同的key

快来打我* 2022-09-01 14:46 212阅读 0赞

good_id =  [{'goods_id': 9, 'buy_num': 1.0}, {'goods_id': 8, 'buy_num': 8.0}, {'goods_id': 7, 'buy_num': 4.0}, {'goods_id': 9, 'buy_num': 1.0}, {'goods_id': 3, 'buy_num': 1.0}, {'goods_id': 2, 'buy_num': 1.0}, {'goods_id': 6, 'buy_num': 1.0}]
    # reverse=False 默认升序，reverse=True降序
    good_id.sort(key=lambda x: x["goods_id"],reverse=True)#对goods_id排序
    print("good_id==",good_id)
    from operator import itemgetter
    from itertools import groupby
    for id,va in groupby(good_id,key=itemgetter("goods_id")):
        data = {}
        sm = []
        key = None
        for i in va:
            key=i["goods_id"]#对goods_id相同的字段
            x = i["buy_num"]#对buy_num进行相加
            sm.append(x)
    
        data["goods_id"]=key
        data["buy_num"]=sum(sm)
        print("data===",data)

打印语句如下：

good\_id== \[\{'goods\_id': 9, 'buy\_num': 1.0\}, \{'goods\_id': 9, 'buy\_num': 1.0\}, \{'goods\_id': 8, 'buy\_num': 8.0\}, \{'goods\_id': 7, 'buy\_num': 4.0\}, \{'goods\_id': 6, 'buy\_num': 1.0\}, \{'goods\_id': 3, 'buy\_num': 1.0\}, \{'goods\_id': 2, 'buy\_num': 1.0\}\]  
data=== \{'goods\_id': 9, 'buy\_num': 2.0\}  
data=== \{'goods\_id': 8, 'buy\_num': 8.0\}  
data=== \{'goods\_id': 7, 'buy\_num': 4.0\}  
data=== \{'goods\_id': 6, 'buy\_num': 1.0\}  
data=== \{'goods\_id': 3, 'buy\_num': 1.0\}  
data=== \{'goods\_id': 2, 'buy\_num': 1.0\}

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[20210728154453833.png]: /images/20220829/b1ea67a58857459c8c8bde278039864d.png