UVa--Rotating Sentences

骑猪看日落 2022-08-27 12:58 6阅读 0赞

**Rotating Sentences **

In \`\`Rotating Sentences,'' you are asked to rotate a series of input sentences 90 degrees clockwise. So instead of displaying the input sentences from left to right and top to bottom, your program will display them from top to bottom and right to left.

## Input and Output ##

As input to your program, you will be given a maximum of 100 sentences, each not exceeding 100 characters long. Legal characters include: newline, space, any punctuation characters, digits, and lower case or upper case English letters. (NOTE: Tabs are not legal characters.)

The output of the program should have the last sentence printed out vertically in the leftmost column; the first sentence of the input would subsequently end up at the rightmost column.

## Sample Input ##

Rene Decartes once said,
    "I think, therefore I am."

## Sample Output ##

"R
    Ie
     n
    te
    h 
    iD
    ne
    kc
    ,a
     r
    tt
    he
    es
    r
    eo
    fn
    oc
    re
    e
     s
    Ia
     i
    ad
    m,
    .
    "

解析：最近看刘汝佳的算法入门，上面的配套习题是UVa Online Judge上面的习题，所以就尝试的做了做，自我感觉上面的题不适合入门，首先感觉读题上面有点困难，可能是因为自己英语太水了，其次感觉题目说的不清不楚的，比如这道有两个易错点， 首先，当某行的字数长度不够时要输出空格，但是题目中并未找到说明哈 然后，就是提示的格式错误，最后一行一定要输出回车，不知道因为这wa了多少 除了这，剩下的就是水题了哈！ #include <iostream>
    #include <string>
    using std::endl;
    using std::cin;
    using std::cout;
    using std::string;
    int main()
    {
    #ifdef LOCAL
    	freopen("input.txt" , "r" , stdin);
    	freopen("output.txt" , "w" , stdout);
    #endif
    	string str[105];
    	int i=0 , maxlength = 0;
    	while(getline(cin , str[i]))
    	{
    		int length = str[i].length();
    		if(length > maxlength)
    			maxlength = length;
    		if(length == 0)
    			break;
    		i++;
    	}
    	for(int k=0;k<maxlength;++k)
    	{
    		for(int j=i-1;j>=0;--j)
    		{
    			if(k<str[j].length())
    				cout << str[j][k];
    			else
    				//如果某行长度不够补齐空格
    				cout << ' ';
    		}
    		//最后一行输出换行符
    		cout << endl;
    	}
    	return 0; 
    }