Spring Boot 快速创建项目入门

淡淡的烟草味﹌ 2022-08-20 03:25 280阅读 0赞

1.创建简单的maven项目

![Image 1][]

2.引入pom.xml

<?xml version="1.0" encoding="UTF-8"?>
    <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
        <modelVersion>4.0.0</modelVersion>
    
        <groupId>com.example</groupId>
        <artifactId>myproject</artifactId>
        <version>0.0.1-SNAPSHOT</version>
    
        <parent>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-parent</artifactId>
            <version>1.4.0.BUILD-SNAPSHOT</version>
        </parent>

<pre name="code" class="html"><dependencies>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>
    </dependencies>

3. To finish our application we need to create a single Java file. Maven will compile sources from  `src/main/java`  by default so you need to create that folder structure, then add a file named  `src/main/java/Example.java` :

import org.springframework.boot.*;
    import org.springframework.boot.autoconfigure.*;
    import org.springframework.stereotype.*;
    import org.springframework.web.bind.annotation.*;
    
    @RestController
    @EnableAutoConfiguration
    public class Example {
    
        @RequestMapping("/")
        String home() {
            return "Hello World!";
        }
    
        public static void main(String[] args) throws Exception {
            SpringApplication.run(Example.class, args);
        }

运行main方法

在浏览器中访问： [localhost:8080][localhost_8080]  显示：

Hello World!

[Image 1]: 
[localhost_8080]: http://localhost:8080/