干支纪年

青旅半醒 2022-08-08 14:37 131阅读 0赞

在我国古代和近代，一直采用干支法纪年。它采用10天干和12地支配合，一个循环周期为60年。  
  
  
    10天干是：甲,乙,丙,丁,戊,己,庚,辛,壬,癸  
    12地支是：子,丑,寅,卯,辰,巳,午,未,申,酉,戌,亥  
  
  
    如果某年是甲子，下一年就是乙丑，再下是丙寅，......癸酉，甲戌，乙亥，丙子，....  
  
  
    总之天干、地址都是循环使用，两两配对。  
  
  
    今年（2012）是壬辰年，1911年辛亥革命

下面的代码根据公历年份输出相应的干支法纪年。已知最近的甲子年是1984年。

<pre name="code" class="cpp">void f(int year)
    {
    	char* x[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
    	char* y[] = {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"};
    	
    	int n = year - 1984;
    	
    	while(n<0) n += 60;
    
    
    	printf("%s%s\n", x[_______], y[_______]);
    }
    
    
    int main(int argc, char* argv[])
    {
    	f(1911);
    	f(1970);
    	f(2012);
    	return 0;
    }

请分析代码逻辑，并推测划线处的代码。  
  
  
答案写在 “解答.txt” 文件中  
  
  
注意：只写划线处应该填的内容，划线前后的内容不要抄写。

#include<stdio.h>
    
    void f(int year)
    {
    	char* x[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
    	char* y[] = {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"};
    	int n = year - 1984;
    	while(n<0) 
    		n += 60;
    	printf("%s%s\n", x[n%10], y[n%12]);//填空1，填空2 
    }
    
    int main(int argc, char* argv[])
    {
    	f(1911);
    	f(1970);
    	f(2012);
    	return 0;
    }