android listview中自定义适配器和复选框

超、凢脫俗 2022-08-06 04:25 181阅读 0赞

下面的代码中报错了，代码如下

@Override
    p
    public View getView(final int position, final View convertView, final ViewGroup parent) {
      
        final ViewHolder viewHolder;
      
        View view = convertView;
      
        if (view == null) {
      
            view = LayoutInflater.from(mContext).inflate(R.layout.row, parent, false);
      
            viewHolder = new ViewHolder();
     
     
     
            viewHolder.textTitle = (TextView) view.findViewById(R.id.title);
      
            viewHolder.checkBox = (CheckBox) view.findViewById(R.id.checkBox);
     
     
     
            viewHolder.checkBox.setTag(position);
      
            view.setTag(viewHolder);
     
     
     
            viewHolder.imageView = (ImageView) view.findViewById(R.id.activity_googlecards_card_imageview);
      
        } else {
      
            viewHolder = (ViewHolder) view.getTag();
      
            viewHolder.checkBox.getTag(position);
      
        }
     
     
     
        viewHolder.textTitle.setText(getItem(position).getTitle());
     
     
     
        viewHolder.checkBox.setChecked(myIntegerArrayList.contains(position));
      
        viewHolder.checkBox.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
      
            @Override
      
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
      
                if (isChecked) {
      
                    myIntegerArrayList.add(position);
      
                } else {
      
                    myIntegerArrayList.remove((Object) position);
      
                }
      
            }
      
        });
     
     
     
        return view;
    }
    }
     
     
     
     
    private static class ViewHolder {
      
        TextView textTitle;
      
        CheckBox checkBox;
    }
    }

该复选框本身工作正常。位置正确添加到我的ArrayList，但如果（假设我选中的项目在位置1）我把listview滚动到底部，然后再滚回去，选中取消了....

### 处理方法 ###

删掉代码viewHolder.checkBox.setTag(position);   
把 viewHolder.checkBox.getTag();放到  onCheckedChanged 中，你按照下面的代码改动

@Override
    
    public View getView(final int position, final View convertView, final ViewGroup parent) {
      
        final ViewHolder viewHolder;
      
        View view = convertView;
      
        if (view == null) {
      
            view = LayoutInflater.from(mContext).inflate(R.layout.row, parent, false);
      
            viewHolder = new ViewHolder();
     
     
     
            viewHolder.textTitle = (TextView) view.findViewById(R.id.title);
      
            viewHolder.checkBox = (CheckBox) view.findViewById(R.id.checkBox);
     
     
     
     
            view.setTag(viewHolder);
     
     
     
            viewHolder.imageView = (ImageView) view.findViewById(R.id.activity_googlecards_card_imageview);
      
        } else {
      
            viewHolder = (ViewHolder) view.getTag();
      
            viewHolder.checkBox.getTag(position);
      
        }
      
        viewHolder.checkBox.setTag(position);
     
     
     
        viewHolder.textTitle.setText(getItem(position).getTitle());
     
     
     
        viewHolder.checkBox.setChecked(myIntegerArrayList.contains(position));
      
        viewHolder.checkBox.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
      
            @Override
      
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
      
                if (isChecked) {
      
                    myIntegerArrayList.add(viewHolder.checkBox.getTag());
      
                } else {
      
                    myIntegerArrayList.remove((Object) viewHolder.checkBox.getTag());
      
                }
      
            }
      
        });
     
     
     
        return view;
    }
    }

让你删掉 viewHolder.checkBox.setTag(position); 是为了 回收ListView,你需要报错位置在tag中，并让 onCheckedChanged 获得到

添加viewHolder.checkBox.getTag() 也是同样的原因

原文地址：[http://www.itmmd.com/201411/119.html ][http_www.itmmd.com_201411_119.html]  
该文章由 [萌萌的IT人][IT] 整理发布,转载须标明出处。

[http_www.itmmd.com_201411_119.html]: http://www.itmmd.com/201411/119.html
[IT]: http://www.itmmd.com/