hdoj 2140 Michael Scofield's letter

小咪咪 2022-08-04 09:27 76阅读 0赞

# Michael Scofield's letter #

**Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)  
Total Submission(s): 3586    Accepted Submission(s): 2074**

Problem Description

I believe many people are the fans of prison break. How clever Michael is!! In order that the message won't be found by FBI easily, he usually send code letters to Sara by a paper crane. Hence, the paper crane is Michael in the heart of Sara. Now can you write a program to help Sara encode the letter from Michael easily?  
The letter from Michael every time is a string of lowercase letters. You should encode letters as the rules below:  
b is ' ', q is ',', t is '!', m is l, i is e, c is a, a is c, e is i, l is m. It is interesting. Are you found that it is just change michael to leahcim?

Input

The input will consist of several cases, one per line.  
Each case is a letter from Michael, the letteres won't exceed 10000.

Output

For each case, output the encode letter one line.

Sample Input

pmicsibforgevibliqbscrct
    ebmovibyout

Sample Output

please forgive me, sara!
    i love you!

题意：输入一个可带空格的字符串；在此字符串中，

把b换成 '  '（空格）,

q 换成 ','（逗号）,

把 t 换成 '!'（感叹号）,

把 m 换成 l（小写字母L）,

把 i 换成 e,

把 c 换成 a,

a 换成 c,

把 e 换成 i

,把 l （小写字母L）换成 m.

思路：建两个数组，把相应的变换的字符放在两个数组的对应位置，然后对输入的字符逐个比较；

#include<stdio.h>
    char str1[]={'b','q','t','l','m','e','i','c','a'};
    char str2[]={' ',',','!','m','l','i','e','a','c'};
    int main(){
    	int c,i;
    	while((c=getchar())!=EOF){
    		for(i=0;str1[i]&&str1[i]!=c;i++);
    		if(str1[i]) putchar(str2[i]);
    		else putchar(c);
    	}
    	return 0;
    }

如有其它意见或建议，欢迎品论

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