python 示例开发程序

一时失言乱红尘 2022-08-02 02:17 204阅读 0赞

1、 求1-100 的素数

# 素数 
    from math import sqrt
    
    i =2
    j=2
    flags = 0
    for i in range(2,101):
            flags = 0
            tmp = int(sqrt(i))
            tmp = tmp + 1
            for j in range(tmp):
                    if j <= 1:
                            continue
                    if i%j == 0:
                            flags = 1
                            break
            if flags == 0:
                    print "%d is a sushu" % (i)

2、关于 文件的一般操作

#coding=utf-8
    # 文件的相关操作, 有中文一定要加这一行
    f = open('lcf.py', 'rw+')
    pointer = f.seek(0, 2)# 2代表尾部，0代表相对偏移
    size = f.tell();
    print 'file: %s, size is %d' % ('lcf/py', size)
    
    pointer = f.seek(0, 0)#第二个0 代表 头部， 1代笔当前位置
    lines = f.read()
    print '1: content is: %s' % lines
    
    
    pointer = f.seek(0, 0)
    lines = f.read(size)
    print '2: content is: %s' % lines
    
    s = 'my name is your king'
    p = f.write(s)
    pointer = f.seek(0, 0)
    lines = f.read(size)
    print '3: content is: %s' % lines
    
    f.close()

3、 class 对象 里面的一些操作

# 对象交换变量，传参以及判断闰年
    class Bird(object):
            a = [10]
            b = [11]
            def __init__(self, words):
                    print "birds happy hapy",words
    
            def swap(self, a, b):
                    c    = a[0]
                    a[0] = b[0]
                    b[0] = c
            laugh = "ha"
            def  str(self):
                    for i in range(5):
                            print self.laugh
            number = 0
            def  panduan(self):
                    if self.number%100 == 0 and self.number%4 == 0 or self.number % 400 == 0 :
                            print "it's ", self.number , "a  run nian "
                    else:
                            print "NULL"
    #lcf = Bird()
    #print lcf.a, lcf.b
    #
    #lcf.swap(lcf.a, lcf.b)
    #print lcf.a, lcf.b
    
    #lcf.str()
    lcf2 = Bird('happy happy!')
    lcf2.number = 2000
    lcf2.panduan()
    
    n1 = [1,34, 2,80,65,5]
    
    for i in n1:
            print i

4、 爬 取 百度贴吧 图片

#爬取百度贴吧一些小图片
    #urllib.urlretriev---将远程数据下载到本地
    import urllib
    import urllib2
    import re
    
    #http://tieba.baidu.com/p/3868127254
    a = raw_input('inpt url:')
    s = urllib2.urlopen(a)
    s1 = s.read()
    
    def getimg(aaa):
            reg = re.compile(r'img.src="(.*?)"')
            #reg = re.compile(r'<title>')
            l = re.findall(reg, aaa)
            tmp =0
            for x in l:
                    tmp += 1
                    urllib.urlretrieve(x, '%s.jpg' % tmp)
    
    #print s1
    getimg(s1)

5、   python 如何  使用 第三方头文件

#calc.py
    #encoding: UTF-8
     
    def adds(a, b):
        return a + b

#test_calc.py 
    #coding: UTF-8
    import nose
    import calc
     
    def test_adds():
        assert calc.adds(1, 2) == 4
     
    if __name__ == '__main__':
        nose.runmodule()

6、a = \[(3, 'URLA'), (6, 'URLB'), (33, 'URLC'), (9, 'URLA'), (365, 'URLD'), (23, 'URLA'), (8, 'URLB')\]  
想找出来相同字符串出现次数大于2的，然后前面的数相加求平均

#-*-coding:utf-8-*-
    a = [(3, 'URLA'), (6, 'URLB'), (33, 'URLC'), (9, 'URLA'), (365, 'URLD'), (23, 'URLA'), (8, 'URLB')]
    c = {}
    sum_a = 0
    num_a = 0
    #初始化
    for j in a:
        c[j[1]] = 0
    print c
    #计数
    for i in a:
        c[i[1]] =  c[i[1]] + 1
    print c
    #满足条件 求解
    for k in c:
            print  k  , c[k]
            if c[k] > 2:
               num_a = num_a + c[k]
               for q  in  a:
                    if q[1] == k:
                            sum_a = sum_a + q[0]
    avg = sum_a / num_a
    print "number:%d,  sum: %d, avg=%d\n" %(num_a,sum_a,avg)

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7、 为别人写的一段小程序  根据ip地理信息库，转换为   192.168.1 , 局域网这种格式   输入 192.168.1.1,192.168.1.255，局域网

#coding=utf-8
    import re
    import sys
    import os
    import socket
    import struct
    import string
    f=open('2.txt', 'r+')
    #print f.read()
    f2=open('out.csv', 'w+')
    
    def getIpNum(ip):
    	num_ip = socket.ntohl(struct.unpack("I", socket.inet_aton(str(ip)))[0])
    #	print num_ip
    	return num_ip
    	
    def getIpStr(ip):
    	num_ip = socket.inet_ntoa(struct.pack('I', socket.htonl(ip)))
    #	print num_ip
    	return num_ip
    
    
    for line in f.readlines():
    #	print line
    	str1 = line.split(",")
    #	for a in str1:
    #		print a
    	start= str1[0]
    	end  = str1[1]
    	city = str1[2]	
    #	print start,end,city       
    	start_s = getIpNum(start)
    	end_s = getIpNum(end)+1
    #	print start_s,end_s
    #	getIpStr(start_s);
    #	getIpStr(end_s);
    	b1 = 0 
            b2 = 0 
            b3 = 0 
            b4 = 0
    	j = 0;
    	for i in range(start_s, end_s):
    		str2 = getIpStr(i);
    		str3 = str2.split('.')
    		a1 = int(str3[0])
    		a2 = int(str3[1])
    		a3 = int(str3[2])
    		a4 = int(str3[3])
    		#print b1,b2,b3,b4
    		if b1 == a1 and b2 == a2 and b3 == a3:
    			continue
    		 
    		b1 = a1; b2 = a2; b3=a3; b4=a4;
    				
    		#print b1,b2,b3,b4
    		out  = str(a1) + '.' + str(a2) + '.' + str(a3)  +','+city	
    		f2.write(out)
    		
    	
    f.close()
    f2.close()

8、调用浏览器

import webbrowser
    chromePath = r'C:\Program Files (x86)\Google\Chrome\Application\new_chrome.exe'            #  例如我的：C:\***\***\***\***\Google\Chrome\Application\chrome.exe
    webbrowser.register('chrome', None, webbrowser.BackgroundBrowser(chromePath))  
    #这里的'chrome'可以用其它任意名字，如chrome111，这里将想打开的浏览器保存到'chrome'
    webbrowser.get('chrome').open('www.baidu.com', new=1,autoraise=True)
    
    #b = webbrowser.open_new('https://blog.csdn.net/wangshubo1989')

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