codeforces 766B Mahmoud and a Triangle

古城微笑少年丶 2022-07-12 05:04 149阅读 0赞

B. Mahmoud and a Triangle

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Mahmoud has *n* line segments, the *i*\-th of them has length *a**i*. Ehab challenged him to use **exactly 3** line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he can win, so he asked you to tell him if he should accept the challenge. Given the lengths of the line segments, check if he can choose exactly 3 of them to form a non-degenerate triangle.

Mahmoud should use exactly 3 line segments, he can't concatenate two line segments or change any length. A non-degenerate triangle is a triangle with positive area.

Input

The first line contains single integer *n* (3 ≤ *n* ≤ 105) — the number of line segments Mahmoud has.

The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1 ≤ *a**i* ≤ 109) — the lengths of line segments Mahmoud has.

Output

In the only line print "YES" if he can choose exactly three line segments and form a non-degenerate triangle with them, and "NO" otherwise.

Examples

input

5
    1 5 3 2 4

output

YES

input

3
    4 1 2

output

Note

For the first example, he can use line segments with lengths 2, 4 and 5 to form a non-degenerate triangle.

给你n条边;   
问你能不能从中挑出3条边来组成一个三角形

#include<cstring>
    #include<algorithm>
    #include<cstdio>
    #include<vector>
    #define pb push_back
    using namespace std;
    const int N = 301010;
    int n,i,a[N];
    int main(){
    	scanf("%d",&n);
    	for (i=1;i<=n;i++){
    		scanf("%d",&a[i]);
    	}
    	sort(a+1,a+1+n);
    	for (i=1;i<n-1;i++)
    	if (a[i]+a[i+1]>a[i+2]){
    		printf("YES\n");
    		return 0;
    	}
    	printf("NO");
    }