Django中实现分页

今天药忘吃喽~ 2022-06-17 03:38 189阅读 0赞

1、view重写Paginator类

from django.core.paginator import Paginator
    
    class JuncheePaginator(Paginator):
        def __init__(self, object_list, per_page, range_num=5, orphans=0, allow_empty_first_page=True):
            Paginator.__init__(self, object_list, per_page, orphans, allow_empty_first_page)
            self.range_num = range_num
    
        def page(self, number):
            self.page_num = number
            return super(JuncheePaginator, self).page(number)
    
        def _page_range_ext(self):
            #print type(self.page_num) 
            #！！！坑
            #type(self.page_num)==unicode导致self.page_num - i没有结果，循环直接结束
    
            self.page_num= int(self.page_num) 
    
            num_count = 2 * self.range_num + 1
            if self.num_pages <= num_count:
                return range(1, self.num_pages + 1)
            num_list = []
            num_list.append(self.page_num)
    
            for i in range(1, self.range_num + 1):
                if self.page_num - i <= 0:
                    num_list.append(num_count + self.page_num - i)
                else:
                    num_list.append(self.page_num - i)
    
                if self.page_num + i <= self.num_pages:
                    num_list.append(self.page_num + i)
                else:
                    num_list.append(self.page_num + i - num_count)
    
            num_list.sort()
            return num_list
        page_range_ext = property(_page_range_ext)

2、view分页方法

def paging(request):
        article = Article.objects.all().order_by('-created_time')
        paginator = JuncheePaginator(article,1) # Show 25 contacts per page
    
        page = request.GET.get('page')
    
        try:
            article = paginator.page(page)
        except PageNotAnInteger:
            # If page is not an integer, deliver first page.
            article = paginator.page(1)
        except EmptyPage:
            # If page is out of range (e.g. 9999), deliver last page of results.
            article = paginator.page(paginator.num_pages)
    
        return render(request, 'blog/paging.html', {
       'contacts': article})

3、分页模板

{% for contact in contacts %} {# Each "contact" is a Contact model object. #} { { contact.full_name|upper }}<br /> ... { { contact.title}} {% endfor %} <div> {% if contacts.has_previous %} <a href='?page={ { contacts.previous_page_number }}'><<</a> {% endif %} {% for page in contacts.paginator.page_range_ext %} {% ifequal page contacts.number %} <a>{ { page }}</a> {% else %} <a href='?page={ { page }}'>{ { page }}</a> {% endifequal %} {% endfor %} {% if contacts.has_next %} <a href='?page={ { contacts.next_page_number }}'>>></a> {% endif %} </div>

4、url设置

urlpatterns = [
            url(r'^pag$', views.paging, name='page_list')
        ]

**init**()函数不用说了吧，就是重载了一下，添加了一个range\_num参数，代表在可能的情况下，当前页左右各显示多少个页标签，默认值为5。  
page()函数是对父类Paginator的page()函数的重写，主要是为了记录当前页。  
核心是\_page\_range\_ext()函数，它实现了我们根据page\_num的情况来返回恰当的页面列表，page\_num取默认值的情况下，如果当前页是8，则我们返回的页数列表就应该是\[3,4,5,6,7,8,9,10,11,12,13\]，但如果说是当前页是2，则会返回\[1,2,3,4,5,6,7,8,9,10,11\]，其余的以此类推。具体算法我就不仔细分析了，大家可以参看源代码，个人感觉还可以优化，但我现在也就能用就行。

参考：[http://www.cnblogs.com/skying555/p/5943232.html][http_www.cnblogs.com_skying555_p_5943232.html]

[http_www.cnblogs.com_skying555_p_5943232.html]: http://www.cnblogs.com/skying555/p/5943232.html