混音算法

傷城~ 2022-06-13 12:42 194阅读 0赞

http://blog.csdn.net/chinabinlang/article/details/8086443

混音算法：

## 混音算法 ##

Hi !!!!  
  
I am not sure weather I have fully understood your question or not, I persume that you are asking   
"How can we mix two or more audio stream", If this is the question then I am explaning below the   
mixing of the two audio stream (You Can Mix More Audio Stream),  
  
Step 1,   
  
Get the Raw data of the two files, (Example, of the sample 8bit and 8Kh, means one sample is of  
8bit)  
  
  
Step 2   
  
Let the two audio signal be A and B respectively, the range is between 0 and 255. Where A and B are the  
Sample Values (Each raw data) And store the resultant into the Y  
  
If Both the samples Values are possitve  
  
**Y = A + B - A \* B / 255**   
  
Where Y is the resultant signal which contains both signal A and B, merging two audio streams into single   
stream by this method solves the problem of overflow and information loss to an extent.   
  
  
If the range of 8-bit sampling is between -127 to 128   
  
If both A and B are negative **Y = A +B - (A \* B / (-127)) **  
Else **Y = A + B - A \* B / 128 **  
  
  
Similarly for the nbit (ex 16bit data)  
  
For n-bit sampling audio signal   
  
  
If both A and B are negative **Y = A + B - (A \* B / (-(2 pow(n-1) -1))) **  
Else **Y = A + B - (A \* B / (2 pow(n-1)) **  
  
  
Step 3.  
  
Add the Header to the Resultant (mixed) data and play back.  
  
If some thing is unclear and ambigious let me know.  
  
Regards  
Ranjeet Gupta.

还有简单C程序示意代码，但是其中包含了核心[算法][Link 1]：

\#include <stdio.h>  
\#include <string.h>  
\#include <stdlib.h>  
\#include <math.h>  
  
int main(int argc,char \*argv\[\]) \{  
char mixname\[255\];  
FILE \*pcm1, \*pcm2, \*mix;  
char sample1, sample2;  
int value;  
  
pcm1 = fopen(argv\[1\],"r");  
pcm2 = fopen(argv\[2\],"r");  
  
strcpy (mixname, argv\[1\]);  
strcat (mixname, "\_temp.wav");  
mix = fopen(mixname, "w");  
  
while(!feof(pcm1)) \{  
  
sample1 = fgetc(pcm1);  
sample2 = fgetc(pcm2);  
  
if ((sample1 < 0) && (sample2 < 0)) \{  
value = sample1 + sample2 - (sample1 \* sample2 / -(pow(2,16-1)-1));  
\}else\{  
value = sample1 + sample2 - (sample1 \* sample2 / (pow(2,16-1)-1));  
\}  
  
fputc(value, mix);  
\}  
  
  
fclose(pcm1);  
fclose(pcm2);  
fclose(mix);  
  
return 0;  
\}

[Link 1]: http://lib.csdn.net/base/datastructure