python将数据写入excel文件时报错ew = ExcelWriter(workbook=wb) TypeError: init() takes exactly 3 arguments

拼搏现实的明天。 2022-06-03 09:49 169阅读 0赞

**问题简介：**

python利用openpyxl 将数据写入excel文件时，以前都正常运行，现在忽然报错如下：

ew = ExcelWriter(workbook=wb)  TypeError: \_\_init\_\_() takes exactly 3 arguments

问题细节：

Traceback (most recent call last):
      File "/Users/a6/Downloads/PycharmProjects/hive/logserver_new/get_interact_data_from_hive.py", line 317, in <module>
        obj_handle_excel.run_main_for_change_txt_to_excel(in_txt_filename,in_head_row_name_list,out_save_excel_filename)
      File "/Users/a6/Downloads/PycharmProjects/hive/logserver_new/save_txt_to_excel.py", line 125, in run_main_for_change_txt_to_excel
        self.__write_to_excel_with_openpyxl(dataset,out_save_excel_filename,in_head_row_name_list)
      File "/Users/a6/Downloads/PycharmProjects/hive/logserver_new/save_txt_to_excel.py", line 91, in __write_to_excel_with_openpyxl
        ew = ExcelWriter(workbook=wb)
    TypeError: __init__() takes exactly 3 arguments (2 given)

**报错代码：**

import sys
    reload(sys)
    sys.setdefaultencoding("utf-8")
    # workbook相关
    from openpyxl.workbook import Workbook
    # 万恶的ExcelWriter，妹的封装好了不早说，封装了很强大的excel写的功能
    from openpyxl.writer.excel import ExcelWriter
    # 一个eggache的数字转为列字母的方法
    #from openpyxl.cell import get_column_letter
    from openpyxl.utils import get_column_letter
    from openpyxl.reader.excel import load_workbook
    def write_to_excel_with_openpyxl(records_list,save_excel_name,head_row_stu_arrive_star):
        # 新建一个workbook
        wb = Workbook()
        # add 1225
        '''
        from zipfile import ZipFile, ZIP_DEFLATED
        archive = ZipFile(save_excel_name, 'w', ZIP_DEFLATED)
        ew = ExcelWriter(workbook=wb,archive=archive)
        '''
        # 新建一个excelWriter
        ew = ExcelWriter(workbook=wb)
    
        # 设置文件输出路径与名称
        dest_filename = save_excel_name.decode('utf-8')
        # 第一个sheet是ws
        ws = wb.worksheets[0]
        # 设置ws的名称
        ws.title = "range names"
        # 写第一行，标题行
        for h_x in range(1,len(head_row_stu_arrive_star)+1):
            h_col=get_column_letter(h_x)
            #print h_col
            ws.cell('%s%s' % (h_col, 1)).value = '%s' % (head_row_stu_arrive_star[h_x-1])
    
        # 写第二行及其以后的那些行
        i = 2
        for record in records_list:
            #print record
            #print type(record)
            record_list=str(record).strip().split("\t")
            #return -2
            for x in range(1,len(record_list)+1):
                col = get_column_letter(x)
                ws.cell('%s%s' % (col, i)).value = '%s' % (record_list[x-1].decode('utf-8'))
            i += 1
        # 写文件
        ew.save(filename=dest_filename)

**解决方案**

方案（一）：

将以下两行代码：
    # 新建一个excelWriter
        ew = ExcelWriter(workbook=wb)
    换成如下3行代码：
        from zipfile import ZipFile, ZIP_DEFLATED
        archive = ZipFile(save_excel_name, 'w', ZIP_DEFLATED)
        ew = ExcelWriter(workbook=wb,archive=archive)
         即可运行成功

方案（二）

其实不建议用创建ExcelWriter对象去写文件了
    可以将以下部分注释：
        # 新建一个excelWriter
        ew = ExcelWriter(workbook=wb)
    和
      # 写文件
        ew.save(filename=dest_filename)
    然后将  # 写文件
        ew.save(filename=dest_filename)
    直接换成
    wb.save(filename=dest_filename)
    就可以了

原因分析：

通过读了一下openpyxl.writer.excel的源码，应该是新版的ExcelWriter对象初始化时多了一个archive参数，所以要写成上面这样。源码如下：

class ExcelWriter(object):
        """Write a workbook object to an Excel file."""
    
        def __init__(self, workbook, archive):
            self._archive = archive
            self.workbook = workbook
            self.manifest = Manifest()
            self.vba_modified = set()
            self._tables = []
            self._charts = []
            self._images = []
            self._drawings = []
            self._comments = []

**参考网址：**

**http://www.codes51.com/itwd/4451357\_2.html**