java读取pfx格式的证书-并获取公钥私钥

╰半橙微兮° 2022-05-31 14:27 373阅读 0赞

package com.hgh.javase.security;
    
    import java.io.FileInputStream;
    import java.security.KeyStore;
    import java.security.PrivateKey;
    import java.security.PublicKey;
    import java.security.cert.Certificate;
    import java.util.Enumeration;
    
    public class ReadPFX {  
        public ReadPFX (){  
        }  
        //转换成十六进制字符串 
        public static String Byte2String(byte[] b) {  
            String hs="";  
            String stmp="";  
    
            for (int n=0;n<b.length;n++) {  
                stmp=(java.lang.Integer.toHexString(b[n] & 0XFF));  
                if (stmp.length()==1) hs=hs+"0"+stmp;  
                else hs=hs+stmp;  
                //if (n<b.length-1) hs=hs+":"; 
            }  
            return hs.toUpperCase();  
        }  
    
        public static byte[] StringToByte(int number) {   
            int temp = number;   
            byte[] b=new byte[4];   
            for (int i=b.length-1;i>-1;i--){   
                b[i] = new Integer(temp&0xff).byteValue();//将最高位保存在最低位 
                temp = temp >> 8; //向右移8位 
            }   
            return b;   
        }   
         public  PrivateKey GetPvkformPfx(String strPfx, String strPassword){  
            try {  
                KeyStore ks = KeyStore.getInstance("PKCS12");  
                FileInputStream fis = new FileInputStream(strPfx);  
                // If the keystore password is empty(""), then we have to set 
                // to null, otherwise it won't work!!! 
                char[] nPassword = null;  
                if ((strPassword == null) || strPassword.trim().equals("")){  
                    nPassword = null;  
                }  
                else  
                {  
                    nPassword = strPassword.toCharArray();  
                }  
                ks.load(fis, nPassword);  
                fis.close();  
                System.out.println("keystore type=" + ks.getType());  
                // Now we loop all the aliases, we need the alias to get keys. 
                // It seems that this value is the "Friendly name" field in the 
                // detals tab <-- Certificate window <-- view <-- Certificate 
                // Button <-- Content tab <-- Internet Options <-- Tools menu 
                // In MS IE 6. 
                Enumeration enumas = ks.aliases();  
                String keyAlias = null;  
                if (enumas.hasMoreElements())// we are readin just one certificate. 
                {  
                    keyAlias = (String)enumas.nextElement();   
                    System.out.println("alias=[" + keyAlias + "]");  
                }  
                // Now once we know the alias, we could get the keys. 
                System.out.println("is key entry=" + ks.isKeyEntry(keyAlias));  
                PrivateKey prikey = (PrivateKey) ks.getKey(keyAlias, nPassword);  
                Certificate cert = ks.getCertificate(keyAlias);  
                PublicKey pubkey = cert.getPublicKey();  
                System.out.println("cert class = " + cert.getClass().getName());  
                System.out.println("cert = " + cert);  
                System.out.println("public key = " + pubkey);  
                System.out.println("private key = " + prikey);  
                return prikey;  
            }  
            catch (Exception e)  
            {  
                e.printStackTrace();  
            }  
            return null;  
        }
    
         public static void main(String[] args) throws Exception {
             String strPfx = "G:\\workspaceOfJava\\javaSe_test\\testfile\\联想测试pfx证书-密码123.pfx";
             String strPassword ="123";
              KeyStore ks = KeyStore.getInstance("PKCS12");  
              FileInputStream fis = new FileInputStream(strPfx);  
              // If the keystore password is empty(""), then we have to set 
              // to null, otherwise it won't work!!! 
              char[] nPassword = null;  
              if ((strPassword == null) || strPassword.trim().equals("")){  
                  nPassword = null;  
              }  
              else  
              {  
                  nPassword = strPassword.toCharArray();  
              }  
              ks.load(fis, nPassword);  
              fis.close();  
              System.out.println("keystore type=" + ks.getType());  
              // Now we loop all the aliases, we need the alias to get keys. 
              // It seems that this value is the "Friendly name" field in the 
              // detals tab <-- Certificate window <-- view <-- Certificate 
              // Button <-- Content tab <-- Internet Options <-- Tools menu 
              // In MS IE 6. 
              Enumeration enumas = ks.aliases();  
              String keyAlias = null;  
              if (enumas.hasMoreElements())// we are readin just one certificate. 
              {  
                  keyAlias = (String)enumas.nextElement();   
                  System.out.println("alias=[" + keyAlias + "]");  
              }  
              // Now once we know the alias, we could get the keys. 
              System.out.println("is key entry=" + ks.isKeyEntry(keyAlias));  
              PrivateKey prikey = (PrivateKey) ks.getKey(keyAlias, nPassword);  
              Certificate cert = ks.getCertificate(keyAlias);  
              PublicKey pubkey = cert.getPublicKey();  
              System.out.println("cert class = " + cert.getClass().getName());  
              System.out.println("cert = " + cert);  
              System.out.println("public key = " + pubkey);  
              System.out.println("private key = " + prikey);  
        }
    }

keystore type=PKCS12
    alias=[51d5a154-415e-4b1b-a055-bb37858ca95a]
    is key entry=true
    cert class = sun.security.x509.X509CertImpl
    cert = [
    [
      Version: V3
      Subject: O="iTrusChina Co.,Ltd.", OU=Lenovo Project, CN=测试证书20180223, OU=QXCD - 33333, OU=TaxCD - 22222, OU=AgencyID - 11111, EMAILADDRESS=13076684@q123123.com
      Signature Algorithm: SHA1withRSA, OID = 1.2.840.113549.1.1.5
    
      Key:  Sun RSA public key, 2048 bits
      modulus: 22657557413401284100317094122201793054162429174129431065947590647854190906608370581286403391341087763841097975687068701429936152897071539889422949403226598003536587449975692615847706829935556655811895258170702116834985572238495571627042731572846922335830615637175517376649775332008195580962533786663755913965907159282213259680423901869255714119163043711206221551766213650295141599478801968859399127722270154565860981431180272488351937142179175776325777949972384300433866258071941139117596804563616993083186036901020114838205796878318295684796020281687231710152726135818054983898634643653967742508133763124702016417333
      public exponent: 65537
      Validity: [From: Fri Feb 23 16:02:18 CST 2018,
     To: Sat Feb 23 16:02:18 CST 2019]
      Issuer: CN=iTrusChina Class 2 Enterprise Subscriber CA - G3, OU=China Trust Network, O=iTrusChina, C=CN
      SerialNumber: [    3d94cfc7 94b6bec0 90f6a2ac 8c3f270b ee9bddc7]
    
    Certificate Extensions: 3
    [1]: ObjectId: 2.5.29.19 Criticality=false BasicConstraints:[ CA:false PathLen: undefined ] [2]: ObjectId: 2.5.29.31 Criticality=false CRLDistributionPoints [ [DistributionPoint: [URIName: http://topca.itrus.com.cn/public/itruscrl?CA=2C1D97288DE14F85C6640698FB24739AF47DFD1A] ]] [3]: ObjectId: 2.5.29.15 Criticality=false KeyUsage [ DigitalSignature Key_Encipherment ] ] Algorithm: [SHA1withRSA] Signature: 0000: 5B EE E7 0C 11 FF 50 0E 04 8F B8 09 7F F7 BF 0E [.....P......... 0010: A5 5C B6 BB F7 78 DE EC AF 32 9A C1 02 9A 7B 5E .\...x...2.....^ 0020: 23 19 9D 8D 8C 47 16 0B AA F0 92 EF 29 51 5B 3E #....G......)Q[> 0030: 03 E5 4F 18 86 DC ED 4C 63 29 3B E6 06 7A 1C 92 ..O....Lc);..z.. 0040: 20 1D 60 2B 42 C5 C3 B6 98 61 A0 8E 20 FF 0F 33 .`+B....a.. ..3 0050: CA F0 32 C8 8B 2C 64 D7 99 4F FC 4F 98 22 4E D3 ..2..,d..O.O."N. 0060: 6A E3 0E F8 A7 2D 04 AD 37 39 23 4C 21 09 C4 8F j....-..79#L!... 0070: 9D 7E 4D 5B 5C C9 25 4F BB EC 6F 80 C8 B8 F0 CE ..M[\.%O..o..... 0080: BD D8 E6 E5 88 88 DB 7B BA 64 E2 57 E3 0F ED 55 .........d.W...U 0090: 74 A6 77 AD 9F CC 78 07 BD 69 7E 6C D3 B5 7E BE t.w...x..i.l.... 00A0: 0D DF 47 40 D0 BE 00 08 F5 3B AE C6 70 0B BB DD ..G@.....;..p... 00B0: 51 50 20 3F CF AD 96 BC 69 0B B3 F3 02 16 D3 DE QP ?....i....... 00C0: 31 7B 78 A2 92 C3 00 E1 24 22 39 41 F6 BD 31 7C 1.x.....$"9A..1. 00D0: 8A 1B 73 0E 59 23 2A 2E 6C 9A 34 8B CB 2F E8 24 ..s.Y#*.l.4../.$ 00E0: 33 07 19 8B 55 D6 5E C9 A5 92 F2 CB 38 1E 37 3F 3...U.^.....8.7? 00F0: B0 20 0C 64 60 03 17 4C C9 CE 7E 67 C5 98 BF F3 . .d`..L...g.... ] public key = Sun RSA public key, 2048 bits modulus: 22657557413401284100317094122201793054162429174129431065947590647854190906608370581286403391341087763841097975687068701429936152897071539889422949403226598003536587449975692615847706829935556655811895258170702116834985572238495571627042731572846922335830615637175517376649775332008195580962533786663755913965907159282213259680423901869255714119163043711206221551766213650295141599478801968859399127722270154565860981431180272488351937142179175776325777949972384300433866258071941139117596804563616993083186036901020114838205796878318295684796020281687231710152726135818054983898634643653967742508133763124702016417333 public exponent: 65537 private key = sun.security.rsa.RSAPrivateCrtKeyImpl@9f22d