shell获取CPU使用量

た入场券 2022-05-31 05:13 237阅读 0赞

#功能：计算CPU的利用率,选取采样点
    #计算公式：
    #方法1：cpu usage=(idle2-idle1)/(cpu2-cpu1)*100
    #方法2: cpu usage=[(user_2 +sys_2+nice_2) - (user_1 + sys_1+nice_1)]/(total_2 - total_1)*100
    #方法3:(本脚本采用)
    #total_0=USER[0]+NICE[0]+SYSTEM[0]+IDLE[0]+IOWAIT[0]+IRQ[0]+SOFTIRQ[0]
    #total_1=USER[1]+NICE[1]+SYSTEM[1]+IDLE[1]+IOWAIT[1]+IRQ[1]+SOFTIRQ[1]
    #cpu usage=(IDLE[0]-IDLE[1]) / (total_0-total_1) * 100
      
    ##echo user nice system idle iowait irq softirq
    CPULOG_1=$(awk '/\<cpu\>/{print $2" "$3" "$4" "$5" "$6" "$7" "$8}' /proc/stat)
    SYS_IDLE_1=$(echo $CPULOG_1 | awk '{print $4}')
    Total_1=$(echo $CPULOG_1 | awk '{print $1+$2+$3+$4+$5+$6+$7}')
     
    sleep 5
     
    CPULOG_2=$(awk '/\<cpu\>/{print $2" "$3" "$4" "$5" "$6" "$7" "$8}' /proc/stat)
    SYS_IDLE_2=$(echo $CPULOG_2 | awk '{print $4}')
    Total_2=$(echo $CPULOG_2 | awk '{print $1+$2+$3+$4+$5+$6+$7}')
     
    SYS_IDLE=`expr $SYS_IDLE_2 - $SYS_IDLE_1`
     
    Total=`expr $Total_2 - $Total_1`
     
    #method 1
    #SYS_USAGE=`expr $SYS_IDLE/$Total*100 |bc -l`
    #SYS_Rate=`expr 100-$SYS_USAGE |bc -l`
     
    #method2
    tmp_rate=`expr 1-$SYS_IDLE/$Total | bc -l`
    SYS_Rate=`expr $tmp_rate*100 | bc -l`
     
    #display
    Disp_SYS_Rate=`expr "scale=3; $SYS_Rate/1" |bc`
    echo $Disp_SYS_Rate%

![70][]

这里面采用的方法是间隔5秒钟读取/proc/stat文件，并且通过计算两者之间的差值来确定CPU的使用量。这种计算方法不准确，因为这种线性的数值就得实时动态的去获取，但是本脚本采用的方法是只获取前后5秒的数值采样，计算差值，这里面的误差一定很大，本文只是通过这个脚本了解一下获取CPU资源的过程。

## 方式二： ##

#!/bin/bash
    
    interval=1
    cpu_num=`cat /proc/stat | grep cpu[0-9] -c`
    for((i=0;i<${cpu_num};i++))
    {
        start=$(cat /proc/stat | grep "cpu$i" | awk '{print $2" "$3" "$4" "$5" "$6" "$7" "$8}')
        start_idle[$i]=$(echo ${start} | awk '{print $4}')
        start_total[$i]=$(echo ${start} | awk '{printf "%.f",$1+$2+$3+$4+$5+$6+$7}')
    }
    start=$(cat /proc/stat | grep "cpu " | awk '{print $2" "$3" "$4" "$5" "$6" "$7" "$8}')
    start_idle[${cpu_num}]=$(echo ${start} | awk '{print $4}')
    start_total[${cpu_num}]=$(echo ${start} | awk '{printf "%.f",$1+$2+$3+$4+$5+$6+$7}')
    sleep ${interval}
    for((i=0;i<${cpu_num};i++))
    {
        end=$(cat /proc/stat | grep "cpu$i" | awk '{print $2" "$3" "$4" "$5" "$6" "$7" "$8}')
        end_idle=$(echo ${end} | awk '{print $4}')
        end_total=$(echo ${end} | awk '{printf "%.f",$1+$2+$3+$4+$5+$6+$7}')
        idle=`expr ${end_idle} - ${start_idle[$i]}`
        total=`expr ${end_total} - ${start_total[$i]}`
        idle_normal=`expr ${idle} \* 100`
        cpu_usage=`expr ${idle_normal} / ${total}`
        cpu_rate[$i]=`expr 100 - ${cpu_usage}`  
    }
    end=$(cat /proc/stat | grep "cpu " | awk '{print $2" "$3" "$4" "$5" "$6" "$7" "$8}')
    end_idle=$(echo ${end} | awk '{print $4}')
    end_total=$(echo ${end} | awk '{printf "%.f",$1+$2+$3+$4+$5+$6+$7}')
    idle=`expr ${end_idle} - ${start_idle[$i]}`
    total=`expr ${end_total} - ${start_total[$i]}`
    idle_normal=`expr ${idle} \* 100`
    cpu_usage=`expr ${idle_normal} / ${total}`
    cpu_rate[${cpu_num}]=`expr 100 - ${cpu_usage}`
    
    
    echo "cpu_num" : ${cpu_num},
    echo "cpu_used" : "${cpu_rate[${cpu_num}]}",

[70]: /images/20220531/d61f43735f2646289d38667f65f550f4.png