1081. Rational Sum (20)

深藏阁楼爱情的钟 2022-05-29 13:26 140阅读 0赞

Given N rational numbers in the form "numerator/denominator", you are supposed to calculate their sum.

**Input Specification:**

Each input file contains one test case. Each case starts with a positive integer N (<=100), followed in the next line N rational numbers "a1/b1 a2/b2 ..." where all the numerators and denominators are in the range of "long int". If there is a negative number, then the sign must appear in front of the numerator.

**Output Specification:**

For each test case, output the sum in the simplest form "integer numerator/denominator" where "integer" is the integer part of the sum, "numerator" < "denominator", and the numerator and the denominator have no common factor. You must output only the fractional part if the integer part is 0.

**Sample Input 1:**

5
    2/5 4/15 1/30 -2/60 8/3

**Sample Output 1:**

3 1/3

**Sample Input 2:**

2
    4/3 2/3

**Sample Output 2:**

**Sample Input 3:**

3
    1/3 -1/6 1/8

**Sample Output 3:**

7/24

--------------------

题目大意：

代码：

#include<stdio.h>
    long long gcd(long long a,long long b)
    {
        if(b==0)
            return a;
        else
            return gcd(b,a%b);
    }
    long long positiveInteger(long long n)
    {
        return n>0?n:-n;
    }
    int main()
    {
        long long i,j,n,m,k,t,numerators,denominators;
        scanf("%lld",&n);
        for(i=0;i<n;i++)
        {
            scanf("%lld/%lld",&k,&t);
            if(i==0)
            {
                numerators=k;
                denominators=t;
            }
            else
            {
                long long tmp=(denominators*t)/gcd(denominators,t);
                numerators=numerators*(tmp/denominators)+k*(tmp/t);
                denominators=tmp;
            }
            m=gcd(numerators,denominators);
            numerators/=m;
            denominators/=m;
        }
        if(positiveInteger(numerators)%denominators==0)
        {
            printf("%lld\n",numerators/denominators);
        }
        else
        {
            if(positiveInteger(numerators)>denominators)
            {
                printf("%lld ",numerators/denominators);
            }
            printf("%lld/%lld\n",numerators%denominators,denominators);
        }
    }