设计一个函数，传入两个年月日，算出间隔的天数

àì夳堔傛蜴生んèń 2022-05-29 11:57 197阅读 0赞

def days(year1,month1,day1,year2,month2,day2):
        list1=[1,3,5,7,8,10,12];
        list2=[4,6,9,11];
        day=0;
        # 先算出year1和year2之间年的总天数
        for i in range(year2+1,year1):
            if(i%4==0 and i%100!=0 or i%400==0):
                day+=366;
            else:
                day+=365;
        # 这个是算出year1年1月1日到month1月day1日的天数，直接加到day上
        for i in range(1,month1):
            if(i in list1):
                day+=31;
            elif(i in list2):
                day+=30;
            else:
                if (year1 % 4 == 0 and year1 % 100 != 0 or year1 % 400 == 0):
                    day+=29;
                else:
                    day+=28;
        day+=day1;
    
    
        # 这个是算year2年1月1日到 month2月day2日的天数 ---  day0
        day0=0;
        for i in range(1,month2):
            if (i in list1):
                day0 += 31;
            elif (i in list2):
                day0 += 30;
            else:
                if (year2 % 4 == 0 and year2 % 100 != 0 or year2 % 400 == 0):
                    day0 += 29;
                else:
                    day0 += 28;
        day0+=day2;
    
        # 判断year2是闰年还是平年  day3是求year2这一年剩下的天数
        if (year2 % 4 == 0 and year2 % 100 != 0 or year2 % 400 == 0):
            day3=366-day0;
        else:
            day3=365-day0;
    
        # 总天数
        allday=day+day3;
        print(allday);
    year1=int(input('输入年'));
    month1=int(input('输入月'));
    day1=int(input('输入天'));
    year2=int(input('输入年'));
    month2=int(input('输入月'));
    day2=int(input('输入天'));
    days(year1,month1,day1,year2,month2,day2);